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Georgia [21]
2 years ago
6

Find the sum of the given polynomials. 5m + 2n, n - 3m, and 7 - 3n

Mathematics
1 answer:
Nataly_w [17]2 years ago
7 0
5m+2n+n-3m+7-3n =2m +7
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Gina’s kitten weighs 5 ounces. Of the kitten gains 3 ounces every week, how many ounces will the kitten weigh in 6 weeks?
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23 ounces

Step-by-step explanation:

3x6=18 +5 = 23

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Write the equation of the line that goes through<br> the points (-3, -2) and (4, 5).
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Find the slope m.

Use the point-slope formula.

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aleksandr82 [10.1K]

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2 years ago
A marketing firm would like to test-market the name of a new energy drink targeted at 18- to 29-year-olds via social media. A st
Anon25 [30]

Answer:

(a) The probability that a randomly selected U.S. adult uses social media is 0.35.

(b) The probability that a randomly selected U.S. adult is aged 18–29 is 0.22.

(c) The probability that a randomly selected U.S. adult is 18–29 and a user of social media is 0.198.

Step-by-step explanation:

Denote the events as follows:

<em>X</em> = an US adult who does not uses social media.

<em>Y</em> = an US adult between the ages 18 and 29.

<em>Z</em> = an US adult between the ages 30 and above.

The information provided is:

P (X) = 0.35

P (Z) = 0.78

P (Y ∪ X') = 0.672

(a)

Compute the probability that a randomly selected U.S. adult uses social media as follows:

P (US adult uses social media (<em>X'</em><em>)</em>) = 1 - P (US adult so not use social media)

                                                   =1-P(X)\\=1-0.35\\=0.65

Thus, the probability that a randomly selected U.S. adult uses social media is 0.35.

(b)

Compute the probability that a randomly selected U.S. adult is aged 18–29 as follows:

P (Adults between 18 - 29 (<em>Y</em>)) = 1 - P (Adults 30 or above)

                                            =1-P(Z)\\=1-0.78\\=0.22

Thus, the probability that a randomly selected U.S. adult is aged 18–29 is 0.22.

(c)

Compute the probability that a randomly selected U.S. adult is 18–29 and a user of social media as follows:

P (Y ∩ X') = P (Y) + P (X') - P (Y ∪ X')

                =0.22+0.65-0.672\\=0.198

Thus, the probability that a randomly selected U.S. adult is 18–29 and a user of social media is 0.198.

6 0
2 years ago
Which of the following is not a characterstic of the sampling distribution of a sample statistic
natita [175]

Answer:

The samples are all drawn from the sample population. Is the not the characteristics of the sampling distribution of a sample statistic. The correct option is b.

Step-by-step explanation:

Samples are drawn from the population not from the sample population.

Therefore drawing samples from a sample population is not a characteristics of the sampling distribution of a sample statistic.

5 0
2 years ago
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