With 128, 134, 140, 146, 152, what’s the next number if the pattern continues?
1 answer:
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Answer:
C. Robbie's glider
Step-by-step explanation:
P.S -The exact question is -
Given - Melissa and Robbie are flying remote control gliders.
The altitude of Melissa's glider, h(s), in feet, is modeled by this function, where sis time, in seconds, after launch.
m(s) = 0.4(s³ - 11s² + 31s – 1)
The altitude of Robbie's glider is modeled by function r, where sis time, in seconds, after launch.
To find - Which glider reaches the greater maximum altitude in the first 6 seconds after launch?
A. Neither glider reaches a maximum altitude on the given interval.
В. Melissa's glider
C. Robbie's glider
D. Both gliders reach the same altitude on the given interval.
Proof -
At t = 6 sec,
Melisa glider is
h(6) = 0.4((0.6)³ - 11(0.6)² + 31(0.6) – 1)
= 0.4( 0.216 - 3.96 + 18.6 - 1 )
= 0.4(13.856) = 5.5424
⇒h(6) = 5.5424
∴ we get
At t = 6 seconds, Melissa glider is at the altitude of 5.54 feet
Now,
From the figure, we can see that,
At t = 6 seconds, Robbie's glider is approximately at an altitude of 13 feet
Now,
As 13 > 5.5
So,
Robbie's glider is at maximum height in 6 seconds after the launch.
So,
The correct option is - C. Robbie's glider
Answer:
D. 2019
Step-by-step explanation:
So I started by rewriting the function f(x)
1000 = 10^3 so
f(x)=10^3 times 1.03^x
1.03 = 103/100 so
f(x)= 10^3 times (103/100)^x
to raise a fraction to a power you just raise the numerator and denominator to that power so
f(x)= 10^3 times 103^x/100^x
change it to exponential form with a base of 10
f(x)=10^3 times 103^x/10^2x
then you can reduce it with the 10^3
f(x)=103^x/10^2x-3
so now that thats in more of a standard form you can find the intersection of the two functions
which is at (9.012,1305.244)
x is the number of years after 2010, so they will be equal ~9 years after 2010, which is 2019.
