#1.
[4x = -12y + 16 and x + 3y = 4]
One answer
#2.
Here, y = 4x + 3
y - 4x = 3
Multiply by 2,
2y - 8x = 6
Compare with second equation,
6 ≠ 3
In short, System of Equation does not have any solution. [ Option D ]
#3.
2y=6
3x-6y=18
Divide first equation by 2: y=3
Substitute y=3 into second equation: 3x-6(3)=18
Solve for x: 3x=36 x=12
Therefore there is only one solution: x=12 y=3
#4.
y - 7x = -14
7y - 49x = -2
Rewrite the first equation as "y =" so that it can be substituted into the second equation and solve for x.
y = 7x - 14
7(7x - 14) - 49x = -2
49x - 98 - 49x = -2
-98 = -2
Since the variables cancel and the equation is not true there is no solution.
The lines are parallel and will not intersect.
