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3 years ago

If C = 2x^2+5x-1 and D = x-1 find an expression that equals C-3D in standard form.

Mathematics

1 answer:

sweet [91]3 years ago

8 0

Answer:

2x^2+2x+2 or 2(x^2+x+1)

Step-by-step explanation:

C = 2x^2+5x-1

D = x-1

C-3D = (2x^2+5x-1) - 3 * (x-1) =2x^2+5x-1-3x+3 =2x^2+2x+2 = 2(x^2+x+1)

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3 five-dollar bills, 3 one-dollar bills, 3 quarters, 1 dime, and 3 nickels. How much money does he have?

VladimirAG [237]

Answer:

He has $19. :)

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3 years ago

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Use the figure below to find the value of y and each angle shown.

igomit [66]

5y - 16 + 3y + 20 = 180 degrees

Combine like terms on the left side

8y + 4 = 180

Subtract 4 from both sides.

8y = 176

Divide both sides by 8

y = 22

Plug 22 into y for each angle.

3y + 20 = 3(22) + 20 = 66 + 20 = 86 degrees

5y - 16 = 5(22) - 16 = 110 - 16 = 94

The angle opposite 5y - 16 also equals 94 because they are vertical angles.

The angle opposite of 3y + 20 also equals 86 because they are vertical angles

6 0

3 years ago

How can I factor this Trinomial? Please show me how!<br><br> 3x² - 8x + 4

Inga [223]

Step-by-step explanation:

3x² - 8x + 4 =

3x² - 6x -2x + 4 =

3x(x-2) -2(x-2) =

(3x -2)(x-2)

7 0

3 years ago

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Find the surface area of the cylinder

Alik [6]

Answer:

Surface Area = 282.6 cm²

Step-by-step explanation:

Formula: SA = 2 $\pi$ rh + 2 $\pi$ r²

SA = 2 $\pi$ rh + 2 $\pi$ r²

SA = 2(3.14)(5)(4) + 2(3.14)(5)

SA = 2(3.14)(5)(4) + 2(3.14)(25)

SA = 125.6 + 157

SA = 282.6 cm²

4 0

3 years ago

A plane flying horizontally at an altitude of 1 mile and a speed of 510 mi/h passes directly over a radar station. Find the rate

sdas [7]

Answer:

442 miles

Step-by-step explanation:

Given

To properly solve this question, I illustrate some given parameters using attached image

From the image, apply Pythagoras theorem

$x^2 + 1^2 = y^2$

Differentiate w.r.t time (t)

$2x\frac{dx}{dt} + 0 = 2y\frac{dy}{dt}$

$2x\frac{dx}{dt} = 2y\frac{dy}{dt}$

Divide both sides by 2

$x\frac{dx}{dt} = y\frac{dy}{dt}$

From the question, we have that the plan travels are 510mi/h.

This implies that:

$\frac{dx}{dt} = 510mi/h$

So, we then calculate the value of x when the distance (y) is 2mi i.e.:

$y = 2mi$

Apply Pythagoras theorem

$x^2 + 1^2 = y^2$

$x^2 + 1^2 = 2^2$

$x^2 + 1 = 4$

$x^2 = 4-1$

$x^2 = 3$

$x = \sqrt 3$

So, the expression becomes:

$x\frac{dx}{dt} = y\frac{dy}{dt}$

$\sqrt 3 * 510 = 2* \frac{dy}{dt}$

$\frac{\sqrt 3 * 510}{2} = \frac{dy}{dt}$

$\sqrt 3 * 255 = \frac{dy}{dt}$

$\frac{dy}{dt} = 255\sqrt 3$

$\frac{dy}{dt} = 255 * 1.7321$

$\frac{dy}{dt} = 441.655$

$\frac{dy}{dt} = 442$

<em>Hence, the distance is 442 miles</em>

7 0

3 years ago