The trick with this problem is that there is no trick - there's no math involved at all, just wordplay. The key is in one-time deposit; what you're looking for isn't a recurring fee, but rather a constant. Now, an equation is made up of three things:
- a variable
- a relational statement in the form of =
- a constant, even if it isn't really there, it's zero
In this case, what you're looking for is the constant in the equation; a value that doesn't change when any variable changes.
The only number in your question that fits the bill is 1200$, since it's a <em>one-time, unchanging value.</em> <em>y </em>is the total amount paid and x represents the months, which are both variables; 400 is tied to x, so it also changes based on months.
Answer:
x=2, y=1
x=-2, y = -1
Step-by-step explanation:
x - 2y = 0
x = 2y
x² - y² = 3
(2y)² - y² = 3
3y² = 3
y² = 1
y = 1 or y = - 1
x = 2 or x = -2
If the machine makes 5 buttons at a time,and each doll gets 5 buttons then one doll is the answer
He would use 9 bills, and 5 coins. (fours $10, one $5, four $1. three quarters, one dime, and one penny). I calculated it all to make sure the total came out as 49.86