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Aleksandr [31]
3 years ago
8

What are the first five terms of n squared minus 1?

Mathematics
1 answer:
Bezzdna [24]3 years ago
4 0

a_n=n^2-1\\\\\text{substitute 1, 2, 3, 4, 5}\\\\a_1=1^2-1=1-1=0\\\\a_2=2^2-1=4-1=3\\\\a_3=3^2-1=9-1=8\\\\a_4=4^2-1=16-1=15\\\\a_5=5^2-1=25-1=24\\\\Answer:\ 0,\ 3,\ 8,\ 15,\ 24

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Step-by-step explanation:

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3 years ago
Solve for x.<br> 3x – 8 &lt; 23 AND<br> - 4x + 26 &gt; 6
11111nata11111 [884]

Answer:

B. x < 5

Step-by-step explanation:

Lets go first with 3x – 8 < 23  then with - 4x + 26 > 6 and after that we put them together. (I will use the < > signs but as I see on the pictures these include the =, being less and greater OR equal).

3x – 8 < 23

Lets sum 8 in both sides:

3x < 23 +8

3x < 31

Now, divide both sides by 3:

3x/3 < 31/3

x < 31/3

Here we found one condition. Lets go with the other inequality for the other condition:

- 4x + 26 > 6

Lest sum 4x in both sides to get a potive x:

- 4x + 26 + 4x > 6 +4x

26 > 6 +4x

Now subtract 6 in both sides

26 - 6 > 6 +4x - 6

20 > 4x

Finally, divide both sides by 4:

20/4 > x or 5 > x (simplifying we get the second)

So, our second condition says that x must be less than 5.

So, putting both conditions together:

x < 5

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x < 5

It is the option B in the image (remember I didnt use the less or equal sign because you didn't included it in the statement).

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