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Elena-2011 [213]
3 years ago
7

Can yal help me with question 3

Mathematics
1 answer:
ra1l [238]3 years ago
8 0
Omg i literally know how to do this but forgot
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3. Formulate 900 lbs of a 35% CP ration using Soybean Meal (46% CP) and Oats (12% CP). How many pounds of soybean meal will be u
Anarel [89]

Answer:

The amount of Soyabean = 608.82 pounds.

The amount of Oats  = 900-608.82 = 291.18 pounds.

Step-by-step explanation:

Given that the Soybean Meal has 46% CP and Oats has 12% CP.

The total amount of ration is 900 lbs of 35% CP.

Let x pounds of Soyabean has been used, so,

the amount of Oats = 900-x lbs.

The CP amount in 900 lbs mixture will be equal to the sum of CP amounts in x lbs Soyabean and 900-x lbs Oats, i.e

35% of 900 = 46% of x + 12% of (900-x)

\Rightarrow \frac{35}{100}\times 900=\frac{46}{100}\times x+\frac{12}{100}\times (900-x)

\Rightarrow  35\times 900 = 46x + 12\times 900 - 12 x

\Rightarrow 34x= 900(35-12)

\Rightarrow x = (900\times 23)/34

\Rightarrow x = 608.82 lbs.

So, the amount of Soyabean = 608.82 pounds.

The amount of Oats  = 900-608.82 = 291.18 pounds.

5 0
3 years ago
Use the discriminant and select whether the roots of 4x 2 - 3x + 3 = 0 are real or imaginary.
MrRa [10]
To find the discriminant we use b^2 - 4ac

equation of 4x^2 - 3x + 3 = 0
                     a      b      c

-3^2 - 4 (4)(3) = -39
if b^2 - 4ac < 0, there are 2 complex roots or...no real roots...in this case imaginary.
8 0
4 years ago
Read 2 more answers
Pat spent $25.89 for a new book bag, $3.15 for a notebook, and $4.59 for a new pack of pens. About how much did he spend?
Shkiper50 [21]
The answer to your question is $33.63
4 0
3 years ago
Read 2 more answers
Someone pleeease help me asap !! thank you so much
ivann1987 [24]

Answer:

Step-by-step explanation:

coordinate points are:

(1,0) , (2,-2) , (0,2) , (-1,0) , (-2,-2)

range = y coordinate

domain = x coorinate

so domain will be {1,2,0,-1,-2}

range will be {0,,2,-2}

Note : Repeated values within the domain or range don't have to be listed more than once.

4 0
3 years ago
Read 2 more answers
A web page designer creates an animation in which a dot on a computer screen has a position of r⃗ =[ 4.2 cm +( 2.5 cm/s2 )t2]i^+
tankabanditka [31]

we are given

r(t)=(4.2cm+(2.5cm/s^2)t^2)i+(5.5cm/s)tj

Firstly, we will plug t=0 and t=2

Calculation of r(0):

r(0)=(4.2cm+(2.5cm/s^2)*0^2)i+(5.5cm/s)*0j

r(0)=4.2i+0j

Calculation of r(2):

r(2)=(4.2cm+(2.5cm/s^2)*2^2)i+(5.5cm/s)*2j

r(2)=(4.2+5)i+(11)j

r(2)=(9.2)i+(11)j

Average velocity:

now, we can use formula

v=\frac{r(2)-r(0)}{2-0}

now, we can plug values

v=\frac{((9.2)i+(11)j)-(4.2i+0j)}{2-0}

v=\frac{5i+11j}{2-0}

v=(2.5cm/s) i+(5.5cm/s)j..............Answer


7 0
3 years ago
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