The perimeter of a rectangular painting is 352 centimeters. If the length of the painting is 98 centimeters, what is its width?

1 answer:

4 0

Thee formula for perimeter is P = 2L + 2W. We know the P is 352 and the L is 98, so fill in the formula accordingly: 352 = 2(98) + 2W and 156 = 2W so W = 78

You might be interested in

Can someone see if I did this right I got 8937.5

garik1379 [7]

It will be $8937.5 because you have to multiply 6500 by .075 (that’s the percent as a decimal) and then multiply the product by 5 years, which will equal to 2437.5. Next you add the interest, which is the total, by the principle, 6500, and you will get the balance of $8537.50. So yes you are correct

7 0

4 years ago

Sin∅=√3-1/2 find approximate value of sec∅(sec∅+tan∅)/1+tan²∅

Neko [114]

Answer:

The approximate value of $f(\theta) = \frac{\sec \theta \cdot (\sec \theta+\tan \theta)}{1+\tan^{2}\theta}$ is 1.366.

Step-by-step explanation:

Let $f(\theta) = \frac{\sec \theta \cdot (\sec \theta+\tan \theta)}{1+\tan^{2}\theta}$ , we proceed to simplify the formula until a form based exclusively in sines and cosines is found. From Trigonometry, we shall use the following identities:

$\sec \theta = \frac{1}{\cos \theta}$ (1)

$\tan\theta = \frac{\sin\theta}{\cos \theta}$ (2)

$\cos^{2}+\sin^{2} = 1$ (3)

Then, we simplify the given formula:

$f(\theta) = \frac{\left(\frac{1}{\cos \theta} \right)\cdot \left(\frac{1}{\cos \theta}+\frac{\sin \theta}{\cos \theta}\right) }{1+\frac{\sin^{2}\theta}{\cos^{2}\theta} }$