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raketka [301]
2 years ago
6

31[tex]\sqrt[n]{x} \sqrt[n]{x}" alt="c-15=31[tex]\sqrt[n]{x} \sqrt[n]{x}" align="absmiddle" class="latex-formula">
Mathematics
2 answers:
Vinil7 [7]2 years ago
6 0
The Answer should be C=31
ExtremeBDS [4]2 years ago
3 0

Answer:

C = 31

Step-by-step explanation:

Solve for c by simplifying both sides of the equation, then isolating the variable.

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What is the height of the tree to the nearest tenth of a foot?
Ugo [173]

Answer:

The height of the tree is approximately 21.4 feet

Step-by-step explanation:

We list out the question parameters first as follows;

The distance from the base of the tree where the angle of elevation is measured, d = 10 feet

The angle of elevation to the top of the tree from 10 feet from the base, θ = 65°

Let 'h' represent the height of the tree, then we have;

The line formed by the angle 65° angle, the height of the tree, 'h', and the distance 'd', form a right triangle with 'h' being the opposite leg to the given reference angle, 65°, and 'd' being the adjacent leg

By trigonometric ratio, we have;

tan(\theta) = \dfrac{Opposite \ leg \ length}{Adjacent\ leg \ length} = \dfrac{h}{d}

∴ h = d × tan(θ)

Plugging in the given values, we get;

h = 10 feet × tan(65°) = 21 feet 5\frac{11}{32} inches

∴  By rounding to the nearest tenth of a foot, the height of the tree, h ≈ 21.4 feet.

3 0
3 years ago
What is the circumference (in inches) of a circle with radius of 5 inches? Use 3.14 for n.
Yuliya22 [10]

Answer:

A. 31.4 in.

Step-by-step explanation:

Formula for the circumference:

C = dπ (d = 2r)

Therefore:

C = 10π

C = 10 · 3.14

C = 31.4 in.

6 0
3 years ago
Read 2 more answers
Help again...its for math offering 15 points
Anettt [7]

Answer:

\tan \dfrac{\theta}2 = \dfrac{1}2

Step by step Explanation:

\sin \theta = \dfrac{\text{Perpendicular} }{\text{Hypotenuse}} = \dfrac{12}{15}\\\\\\\cos \theta = \dfrac{\text{Base}}{\text{Hypotenuse}}= \dfrac{9}{15}\\\\\text{Now,}\\\\\tan \dfrac{\theta}2 = \dfrac{\sin \tfrac{\theta}2}{\cos \tfrac{\theta}2}\\\\\\~~~~~~~~=\dfrac{2\cos \tfrac{\theta}2 \sin \tfrac{\theta}2 }{2\cos^2 \tfrac{\theta}2}~~~~~~;\left[\text{Multiply by}~ 2\cos\tfrac{\theta}2 \right]

         =\dfrac{\sin \theta}{1+ \cos \theta}~~~~~~~~~~~~;[2 \sin x \cos x = \sin 2x ~ \text{and}~ 2\cos^2 x =1+\cos 2x]\\\\\\=\dfrac{\tfrac{12}{15}}{1+ \tfrac{9}{15}}\\\\\\=\dfrac{\tfrac{12}{15}}{\tfrac{24}{15}}\\\\\\=\dfrac{12}{15}\times \dfrac{15}{24}\\\\\\=\dfrac{12}{24}\\\\\\=\dfrac{1}2

4 0
2 years ago
You have to average at least a "90" on your test scores to get an "
Ganezh [65]
The next score is 90 because 85+91+92+92=360/4= 90 average.
4 0
3 years ago
How do you calculate elapsed time?
Valentin [98]
First tell me what elapsed time is
4 0
3 years ago
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