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finlep [7]
3 years ago
7

Can anyone explain dimensional analysis pleaseeee

Mathematics
1 answer:
dimaraw [331]3 years ago
3 0
Is a problem solving method that uses that fact that any number or expression can be multiplied by one without changing it's value.
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1462 divided by 58<br><br> To mixed number
GaryK [48]
Ur answer is 25/6/29 plz give brainliest
6 0
3 years ago
Write the explicit formula that represents the geometric sequence -2, 8, -32, 128
MissTica
So hmm the first term is -2

and if we divide one term by the term before it, we'd get the "common ratio" "r"

so hmm say -32/8 that gives us -4, so r = -4

thus \bf n^{th}\textit{ term of a geometric sequence}\\\\&#10;a_n=a_1r^{n-1}\qquad &#10;\begin{cases}&#10;a_1=\textit{first term}\\&#10;r=\textit{common ratio}\\&#10;----------\\&#10;a_1=-2\\&#10;r=-4&#10;\end{cases}\implies a_n=-2(-4)^{n-1}
6 0
3 years ago
A 2-column table with 7 rows. The first column is labeled x with entries negative 3, negative 2, negative 1, 0, 1, 2, 3. The sec
kondor19780726 [428]

Answer:

2nd

4th

5th

Step-by-step explanation: Took assignment on edge

8 0
3 years ago
Read 2 more answers
A 2.2 kg ball strikes a wall with a velocity of 7.4 m/s to the left. The ball bounces off with a velocity of 6.2 m/s to the righ
Naya [18.7K]

Answer:

The constant force exerted on the ball by the wall is 119.68 N.

Step-by-step explanation:

Consider the provided information.

It is given that the mass of the ball is m = 2.2 kg

The initial velocity of the ball towards left is 7.4 m/s

So the momentum of the ball when it strikes is = 2.2\times 7.4=16.28

The final velocity of the ball is -6.2 m/s

So the momentum of the ball when it strikes back is = 2.2\times -6.2=-13.64

Thus change in moment is: 16.28-(-13.64)=29.92

The duration of force exerted on the ball t = 0.25 s

Therefore, the constant force exerted on the ball by the wall is:

\frac{29.92}{0.25}=119.68

Hence, the constant force exerted on the ball by the wall is 119.68 N.

6 0
3 years ago
Tina loves to read. Before breakfast, she read 21/2 pages, at lunch she read 31⁄5 pages, and after dinner she read 11⁄3 pages. H
MrMuchimi

Answer: 7 1/30

Step-by-step explanation:

Tina loves to read. Before breakfast, she read 2 1/2 pages, at lunch she read 3 1/5 pages, and after dinner she read 1 1/3 pages. To find the total, we add all the pages together. This will be:

2 1/2 + 3 1/5 + 1 1/3

The LCM of 2, 5 and 3 is 30.

= 2 15/30 + 3 6/30 + 1 10/30

= 6 31/30

= 7 1/30.

5 0
3 years ago
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