Question

Please explain how to solve the problem.

Answer 1

Answer:

Part 1) $f(125)=6$

Part 2) $f(-64)=-3$

Step-by-step explanation:

we have

$f(x)=\sqrt[3]{x} +1$

Part 1) Find f(125)

we know that

f(125) is the value of the function f(x) when the value of x is equal to 125

so

For x=125

substitute in the function

$f(125)=\sqrt[3]{125} +1$

Remember that

$125=5^{3}$

substitute

$f(125)=\sqrt[3]{5^{3}} +1$

Applying the power of rule

$\sqrt[3]{5^{3}}=(5^{3})^{\frac{1}{3}}= (5)^{3*\frac{1}{3}}=5$

substitute

$f(125)=5 +1=6$

Part 2) Find f(-64)

we know that

f(-64) is the value of the function f(x) when the value of x is equal to -64

so

For x=-64

substitute in the function

$f(-64)=\sqrt[3]{-64} +1$

Remember that

$-64=-4^{3}$

substitute

$f(-64)=\sqrt[3]{-4^{3}} +1$

Applying the power of rule

$\sqrt[3]{-4^{3}}=(-4^{3})^{\frac{1}{3}}= (-4)^{3*\frac{1}{3}}=-4$

substitute

$f(-64)=-4 +1=-3$