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Anastasy [175]
2 years ago
9

Sofia raised $140 for charity. Her mom gave her some money to get started, and her friends donated the rest of the money Dominic

gave her $75, gave her $, and Julie gave her $30How much did her mom give her? Supportive answer (this is her sister I stole her phone I’m 9)
Mathematics
1 answer:
Katen [24]2 years ago
3 0

Answer:

Step-by-step explanation:

you add 75 plus 30 which is 105 and subtract that by 140 which is 35

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Solve this equation <br> 12y = 30
svp [43]

Answer:

hI!!

Y = 5/2

Step-by-step explanation:

Let's solve your equation step-by-step.

12y=30

Step 1: Divide both sides by 12.

12y/12 30/12

7 0
2 years ago
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There is a sales tax of $6 on an item that costs $88 before tax. The sales tax on a second item is $21 . How much does the secon
zubka84 [21]
6 / 88 = 21/x
cross multiply
(6)(x) = (21)(88)
6x = 1848
x = 1848/6
x = 308 <==
5 0
3 years ago
What is the maximum number of real distinct roots that a quartic equation can have?
choli [55]
An nth degree<span> polynomial can have as many as n real roots.</span>
6 0
3 years ago
Three forces act on a hook. Determine the magnitude of the resultant of the force.
Novay_Z [31]

Use Hooke's law... (just kidding)

Break down each force vector into horizontal and vertical components.

\vec F_1=(1000\,\mathrm N)(\cos30^\circ\,\vec x+\sin30^\circ\,\vec y)\approx(866.025\,\mathrm N)\,\vec x+(500\,\mathrm N)\,\vec y

\vec F_2=(1500\,\mathrm N)(\cos160^\circ\,\vec x+\sin160^\circ\,\vec y)\approx(-1409.54\,\mathrm N)\,\vec x+(513.03\,\mathrm N)\,\vec y

\vec F_3=(750\,\mathrm N)(\cos195^\circ\,\vec x+\sin195^\circ\,\vec y)\approx(-724.444\,\mathrm N)\,\vec x+(-194.114\,\mathrm N)\,\vec y

The resultant force is the sum of these vectors,

\vec F=\displaystyle\sum_{i=1}^3\vec F_i\approx(-1267.96\,\mathrm N)\,\vec x+(818.916\,\mathrm N)\,\vec y

and has magnitude

|\vec F|\approx\sqrt{(-1267.96\,\mathrm N)^2+(818.916\,\mathrm N)^2}\approx1509.42\,\mathrm N

The closest answer is D.

5 0
2 years ago
For a group of 100 people, compute(a) the expected number of days of the year that are birthdays of exactly 3 people.(b) the exp
Scilla [17]

Answer:

Step-by-step explanation:

Leaving leap years, a year contains 365 days.

For a group of 100 people, each person is independent of the other and probability of any day being his birthday has a chance of

\frac{1}{365}

a) Probability that  exactly 3 people have same birthday = \frac{1}{365^3}

Each day is independent of the other

And hence no of days having exactly 3 persons birthday out of 100 persons is binomial with n = 365 and p = \frac{1}{365^3}

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b) Distinct birthdays is binomail with p =1/365 and n = 365

Hence

expected value = np =1

4 0
3 years ago
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