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3 years ago

Evaluate (16/81) to the power 3/4

Mathematics

1 answer:

tensa zangetsu [6.8K]3 years ago

5 0

This reduces nicely if you first notice that 16/81 = (2/3)^4.

Then use the properties of powers (of positive real numbers):

(16/81)^(3/4) = ((2/3)^4)^(3/4) = (2/3)^3 = 8/27

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3/4 of 24 is 3 groups of 6, which is 18. So Han ate 18 less than Tyler, or Han at 6. So you take the 24(x) and you subtract 24 o

aksik [14]

Answer:

Step-by-step explanation:

Let the total amount ate by Tyler and Han be 24

Let the amount Tyler ate be x

Amount Han ate be y

If Tyler ate 3/4 of the total, then Amount ate by Tyler is expressed as;

x = 3/4of 24

x = 3/4×24

x = 3×6

x = 3(6)

x = 18

Hence the amount Tyler ate is 18

If Han ate 18 less than Tyler, the amount ate by Han will be;

Han y = 24-(3/4(24)

y = 24-{3(6)}

y = 24-18

y = 6

Hence the total Han ate is 6

8 0

3 years ago

Please help will give brainlest please quickly and thank you

Papessa [141]

Answer:

y=(4/5)x-(18/5)

Step-by-step explanation:

Slope: 4/5

y=(4/5)x+b

Use (2,-2)

-2=(4/5)(2)+b

b= -18/5

y=(4/5)x-(18/5)

6 0

3 years ago

-7x+2y=18;6x+6y=0 in elimination form

AlexFokin [52]

Step-by-step explanation:

-7x + 2y = 18

6x + 6y = 0

21x - 6y = - 54

6x + 6y = 0

27x = -54

x = -2

6(-2) + 6y = 0

-12 + 6y = 0

6y = 12

y = 2

(-2,2)

4 0

3 years ago

Number 24 ion know the answer

Stels [109]

Answer:

C.620

Step-by-step explanation:

125+185=310

31082=620

8 0

3 years ago

Read 2 more answers

In simplest radical form, what are the solutions to the quadratic equation 6 = x2 - 10/?

pickupchik [31]

Answer:

$x = 5 \± \sqrt{31}$

Step-by-step explanation:

Given

$6 = x^2 - 10x$

Required

The solution in radical form

$6 = x^2 - 10x$

Rewrite as:

$x^2 - 10x - 6 = 0$

Using the quadratic formula, we have:

$x = \frac{-b \± \sqrt{b^2 - 4ac}}{2a}$

Where

a = 1

b = -10

c = -6

So, we have:

$x = \frac{-(-10) \± \sqrt{(-10)^2 - 4*1*(-6)}}{2*1}$

$x = \frac{10 \± \sqrt{100 +24}}{2*1}$

$x = \frac{10 \± \sqrt{124}}{2}$

Split the roots

$x = \frac{10 \± \sqrt{4 * 31}}{2}$

Express $\sqrt 4$ as 2

$x = \frac{10 \± 2\sqrt{31}}{2}$

Split the fraction

$x = \frac{10}{2} \± \frac{2\sqrt{31}}{2}$

$x = 5 \± \sqrt{31}$

5 0

3 years ago