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Ymorist [56]
3 years ago
10

For a group of 100 people, compute(a) the expected number of days of the year that are birthdays of exactly 3 people.(b) the exp

ected number of distinct birthdays.
Mathematics
1 answer:
Scilla [17]3 years ago
4 0

Answer:

Step-by-step explanation:

Leaving leap years, a year contains 365 days.

For a group of 100 people, each person is independent of the other and probability of any day being his birthday has a chance of

\frac{1}{365}

a) Probability that  exactly 3 people have same birthday = \frac{1}{365^3}

Each day is independent of the other

And hence no of days having exactly 3 persons birthday out of 100 persons is binomial with n = 365 and p = \frac{1}{365^3}

Expected value of days = np = \frac{1}{365^2}

b) Distinct birthdays is binomail with p =1/365 and n = 365

Hence

expected value = np =1

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Stells [14]

Answer:

a = 60°

Step-by-step explanation:

From the picture attached,

In the given triangle,

NE and ML are the perpendicular bisectors of two sides of the triangle.

Therefore, m∠MEK = m∠MLK = 90°

Since, sum of interior angles of polygon KLME = 360°

m∠MEK + m∠MLK + m∠EML + m∠EKL = 360°

90° + 90° + 120° + a = 360°

a = 360° - 300°

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5 0
2 years ago
PLEASE HELP!! i dont understand it
andreev551 [17]

Answer:

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3 years ago
Snowy's Snow Cones has a special bubble gum snow cone on sale. The cone is a regular snow cone that has a spherical plece of bub
Aloiza [94]

Draw a diagram to illustrate the problem as shown below.

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2 years ago
45 Points, Question 2 In Attachment. Asap if possible.
Masja [62]

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Equating the coefficient

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2 years ago
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