Question

3x + 3y = 10 -9 - 9 = -30 What is the solution of the following system?

Answer 1

Answer:First x=−y+103

Second −9−9=?−30

−18≠−30

False

Step-by-step explanation:

3x+3y=10

Step 1: Add -3y to both sides.

3x+3y+−3y=10+−3y

3x=−3y+10

Step 2: Divide both sides by 3.

3x3=−3y+103

x=−y+103

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Answer 2

Answer:

1. $x = \frac{10}{3} - y$ 2. False

Step-by-step explanation:

We have two equations

1. $3x + 3y = 10$

2. $-9 - 9 = -30$

Taking equation No 1

$3x + 3y = 10\\Dividing\ both\ sides\ by\ 3\ we\ get\\\frac{3x}{3} + \frac{3y}{3} = \frac{10}{3} \\x + y = \frac{10}{3} \\Now\ subtracting\ y\ from\ both\ sides\ we\ get\\\\x + y - y = 10/3 - y\\x = 10/3 -y$

For equation no 2

-9 -9 = -30

-18 = -30 which is not true