Answer:
108
Step-by-step explanation:
we first add 7+8=15 then 15×2=30 30+6=36 36×2=108
Answer:

Step-by-step explanation:



The total length of the circle is calculated by the following formula:
Lenght = 2.π.r
As r = 4c
Then,
Lenght = 2.π.4
Lenght = 8π centimetrs
Now use the rule of 3
But we have to know:
...<..> ...
Then,
8π ________ 2π <= 360°
x ________ 3π
2π . x = 8π . 3π
x = (8π . 3π) / 2π
x = (8 . 3π)/ 2
x = 12π centimenters
x ~ 37,69 c
Answer:
t= -0.18
Step-by-step explanation:
Isolate t to get the unknown number:
(-4.5t)(49.5t) = 40
Multiply (-4.5t)(49.5t):
(-4.5t)(49.5t) = -222.75t
Now, write full equation:
-222.75t = 40
Isolate t by dividing -222.75 on both sides:

Cancel out left hand side:

Simplify your answer:

Approximate to 2 decimals:

The equation of the line that is perpendicular to 4x - 3y = 10 through the point (-2,4) is 
<u>Solution:</u>
Given, line equation is 4x – 3y = 10
We have to find a line that is perpendicular to 4x – 3y = 10 and passing through (-2, 4)
Now, let us find the slope of the given line,

We know that, slope of a line
slope of perpendicular line = -1

Now, slope of our required line =
and it passes through (-2, 4)
<em><u>The point slope form is given as:</u></em>


Hence the equation of line is found out