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2 years ago

Given the point (-3, 6) and a line y=2x-8, write an equation of a line through the point and parallel to the line.

Mathematics

1 answer:

ch4aika [34]2 years ago

7 0

Answer: y = 2x

Step-by-step explanation:

The equation of a straight line can be represented in the slope intercept form as

y = mx + c

Where

m = slope = (change in the value of y in the y axis) / (change in the value of x in the x axis)

The equation of the given line is

y = 2x - 8

Comparing with the slope intercept form, slope = 2

If two lines are parallel, it means that they have the same slope. Therefore, the slope of the line passing through (- 3,-6) is 2

To determine the intercept, we would substitute m = 2, x = - 3 and

y = - 6 into y = mx + c. It becomes

- 6 = 2 × - 3 + c

- 6 = - 6 + c

c = - 6 + 6 = 0

The equation becomes

y = 2x

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Read 2 more answers

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Andrej [43]

Answer:

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Step-by-step explanation:

We have been given a triangle and we are asked to find the length of AC (b).

We will use law of cosines to find the length of side AC.

$c^{2}=a^{2}+b^{2}-2ab \text{ cos }\theta$

Upon substituting our given values in the formula we will get,

$(AC)^{2}=15^{2}+12^{2}-2\times 15\times 12 \text{ cos}(106)$

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Upon taking square root of both sides of our equation we will be get,

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