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True [87]
3 years ago
14

Suppose that X is a random variable with mean 30 and standard deviation 10. Also suppose that Y is a random variable with mean 2

0 and standard deviation 8. Assume that the correlation between X and Y is 0.4. Find the mean and standard deviation of the random variable Z for each of the following cases. Be sure to show your work. a. Z= 2 + 10X. b. Z = X + Y. c. Z = −5X − 3Y
Mathematics
1 answer:
Bas_tet [7]3 years ago
3 0
Part a: For variable X using z score you have (x-30)/10, replace X for this expression in (a), i mean Z=2+10((x-30)/10) = 2+x-30= put this in the way of z score = (x-18)/1, so the mean is 18 and standard deviation is 1.
Part b: Z=X+Y= (x-30)/10 + (x-20)/8 = solve adding fractions = (18x-440)/80 now divide all the numbers between 18 (because you need to show as z score way) = (x-24.4)/4.4, so the mean is 24.4 and standard deviation is 4.4.
For part c,do the same.
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otez555 [7]

2\frac{3}{4}+3 \frac{5}{8}=6\frac{3}{8}

Solution:

Given expression is 2\frac{3}{4}+3 \frac{5}{8}.

To simplify the expression 2\frac{3}{4}+3 \frac{5}{8}.

Let us first convert the mixed fraction into improper fraction.

2\frac{3}{4}+3 \frac{5}{8}=\frac{(2\times 4) + 3}{4}+ \frac{(3 \times 8)+5}{8}

            =\frac{8+ 3}{4}+ \frac{24+5}{8}

            =\frac{11}{4}+ \frac{29}{8}

Take LCM for the denominators (LCM of 4, 8 = 8) and make the same.

            =\frac{11\times2}{4\times 2}+ \frac{29\times1}{8\times1}

            =\frac{22}{8}+ \frac{29}{8}

            =\frac{51}{8}

Now, divide 51 by 8 and again write it in the mixed fraction.

             =6\frac{3}{8}

2\frac{3}{4}+3 \frac{5}{8}=6\frac{3}{8}

Hence, the simplified answer is 6\frac{3}{8}.

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