The probablity that the sample's mean length is greate than 6.3 inches is0.8446.
Given mean of 6.5 inches,standard deviation of 0.5 inches and sample size of 46.
We have to calculate the probability that the sample's mean length is greater than 6.3 inches is 0.8446.
Probability is the likeliness of happening an event. It lies between 0 and 1.
Probability is the number of items divided by the total number of items.
We have to use z statistic in this question because the sample size is greater than 30.
μ=6.5
σ=0.5
n=46
z=X-μ/σ
where μ is mean and
σ is standard deviation.
First we have to find the p value from 6.3 to 6.5 and then we have to add 0.5 to it to find the required probability.
z=6.3-6.5/0.5
=-0.2/0.5
=-0.4
p value from z table is 0.3446
Probability that the mean length is greater than 6.3inches is 0.3446+0.5=0.8446.
Hence the probability that the mean length is greater than 6.3 inches is 0.8446.
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Answer:
(3x + 10) / (2x + 5)(x - 5).
Step-by-step explanation:
(3/2x+5) + (5/x-5)
= [3(x - 5) + 5(2x + 5) ] / [ (2x + 5)(x - 5)]
= 3x - 15 + 10x + 25 / (2x + 5)(x - 5)
= 13x + 10 / (2x + 5)(x - 5).
Step-by-step explanation:
Simplify the left side:
5x - 20 = 3x + 4
Move all terms containing x to the left side of the equation:
2x - 20 = 4
Move all terms not containing x to the right side of the equation:
2x = 24
Divide each term by 2 and simplify:
x = 12
<span><span> 17
</span><span>2 35
</span> 2
<span> 15
</span><span> 14
</span><span> 1
The remainder ends up to be 1. So it is 17.5. All you need to do, is to look for LCM in 35 and 2. </span></span>
