Answer: the answer is c
Step-by-step explanation:
Answer:
Option b
Step-by-step explanation:
A function is even if and only if f(-x) = f(x).
This means that there is the same value of y for
and for 
Where
is any point belonging to the function .
Therefore you must select a graph whose ordered pairs are of the form
and 
Therefore the correct answer is option b. Assume that each box in the graph equals 1 unit. Then, for x = 2 y = -3 and for x = -2 y = -3. Then it is shown that the function is even.
63 + 36...there is a common factor of 9
9(7 + 4) <== this is equivalent
63 + 36...there is a common factor of 3
3(21 + 12)...but this is not an answer choice...but it is equivalent
If the degree of numerator and denominator are equal, then limit will be leading coefficient of numerator divided by the
leading coefficient of denominator.
So then the limit would be 3/1 =
3.
Alternatively,

Hope this helps.
Answer:
The answer is 0.725 Please mark me brainliest xd