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2 years ago

Question 6 (1 point)

Mathematics

1 answer:

Shalnov [3]2 years ago

8 0

2. Dividing exponential expression with the same base is what the left hand fractional expression is. Z^8/Z^?=z^6. Since all the bases are the same. To get the exponential power 6 on the right we subtract the denominator’s (bottom part of the fraction) exponential power (on the left) from the numerator’s (top part) exponential power.

Then, 8 - ? = 6? 2 is the only number to make the left equal the right side. This, z^8/z^2=z^6

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Answer:

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Step-by-step explanation:

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Que is on pic.i can't able to type in text.

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It's not difficult to compute the values of $A$ and $B$ directly:

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$A=\tan^{-1}(\sin\theta)-\dfrac\pi4$

$B=\displaystyle\int_1^{\csc\theta}\frac{\mathrm dt}{t(1+t^2)}=\int_1^{\csc\theta}\left(\frac1t-\frac t{1+t^2}\right)\,\mathrm dt$
$B=\left(\ln|t|-\dfrac12\ln|1+t^2|\right)\bigg|_{t=1}^{t=\csc\theta}$
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Let's assume $0$ , so that $|\csc\theta|=\csc\theta$ .

Now,

$\Delta=\begin{vmatrix}A&A^2&B\\e^{A+B}&B^2&-1\\1&A^2+B^2&-1\end{vmatrix}$
$\Delta=A\begin{vmatrix}B^2&-1\\A^2+B^2&-1\end{vmatrix}-e^{A+B}\begin{vmatrix}A^2&B\\A^2+B^2&-1\end{vmatrix}+\begin{vmatrix}A^2&B\\B^2&-1\end{vmatrix}$
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There doesn't seem to be anything interesting about this result... But all that's left to do is plug in $A$ and $B$ .

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Step-by-step explanation:

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The length of a rectangle is 4 inches more than its width, and its perimeter is 34 inches. Find the length and width of the

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Answer:

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Step-by-step explanation:

Let

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