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Sedbober [7]
3 years ago
12

Use the area to find the length of jk

Mathematics
1 answer:
enyata [817]3 years ago
6 0
The length of Jk= 2.5 m^2
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Design minimal 2-level AND-OR and NAND-NAND realizations of the following logic function. Draw circuit diagrams of your realizat
Delicious77 [7]

Answer:

Realization :

since there are 3-variable. Therefore 2ⁿ = 2³ = 8

From the attached solution, f(x,y,z) = y' + xz'

also' see the circuit diagrams of my realizations of AND-OR and NAND-NAND

Step-by-step explanation:

See attached picture for minimal 2-level AND-OR and NAND-NAND of the logic function.

f(x,y,z) = y' + xz' was designed from the function  f(x,y,z) = Σm(0,1,4,5,6)

Then, minimal 2-level AND-OR was designed and after was NAND-NAND designed as well.

5 0
3 years ago
let x represent one number and let y represent the other number. use the given conditions to write a system of equations. solve
kiruha [24]

9514 1404 393

Answer:

  (x, y) = (8, 2)

Step-by-step explanation:

The relevant equations are ...

  3x -y = 22

  x +2y = 12

__

We can eliminate y by adding twice the first equation to the second.

  2(3x -y) +(x +2y) = 2(22) +(12)

  7x = 56

  x = 8

Substituting into the first equation gives ...

  3(8) -y = 22

  y = 24 -22 = 2

The first number is 8; the second number is 2.

7 0
3 years ago
Write the quadratic equation whose roots are 5 and 1, and whose leading coefficient is 5
zepelin [54]

Answer: the equation is

5x^2 -30x - 25

Step-by-step explanation:

A quadratic equation is one in which the highest power of the unknown is 2.

The general form of a quadratic equation is expressed as

ax^2 + bx + c

Where c is a constant and a is the leading coefficient

Assuming we want to write the quadratic equation in x, from the information given, the given roots are 5 and 1 and the leading coefficient is 5. We will just multiply the expression by the leading coefficient.

Therefore, the linear factors of the quadratic will be (x-5) and (x-1)

With the leading coefficient as 5, the equation becomes

5(x-5)(x-1)

= 5(x^2 - x - 5x + 5)

= 5(x^2 - 6x + 5)

= 5x^2 -30x - 25

3 0
3 years ago
Sara solved the equation -6(x-2) + 3x = -3(x+3) + 21 What is the solution? <br> pls help :)
kirill115 [55]

To solve you can use inverse operations.

Here are the steps to find the answer:

1. Write out the equation: -6(x-2)+3x= -3(x+3) +21

2. Distribute both sides: -6x+12+3x= -3x-9+21

3. Simplify both sides: -3x+12=-3x+12

4. This equation is true for all values, or infinity, because the equation is the same on both sides

Let me know if you need further explanation. I hope this helps.

6 0
3 years ago
I need to pass this test
g100num [7]

Answer:

C. f⁻¹(x) = 3 - 5x

Step-by-step explanation:

To find the inverse of a function, switch x and y and solve for y.

f(x) = (3 - x)/5

Change f(x) to y.

y = (3 - x)/5

Switch x and y.

x = (3 - y)/5

Multiply both sides by 5.

5x = 3 - y

Subtract 3 from both sides.

5x - 3 = -y

Multiply both sides by -1.

-5x + 3 = y

Switch the sides.

y = -5x + 3

Change the equation.

y = 3 - 5x

3 0
2 years ago
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