Use the area to find the length of jk

A turtle can walk 1/12 of a kilometer in an hour. The turtle is 1/5 o a kilometer away from a pond. At this speed,how long will

eimsori [14]

Answer:

It will take 5/12 hours.

Step-by-step explanation:

Given,

The speed of turtle = $\frac{1}{12}$ km per hour,

Distance covered = $\frac{1}{5}$ km,

Since,

$Speed =\frac{Distance}{Time}$

$\implies Time =\frac{Distance}{Speed}$

Hence, the speed of turtle = $\frac{\text{1}{12}}{\frac{1}{5}}$

$=\frac{5}{12}$ hour.

7 0

3 years ago

What is the area of the regular polygon?

BartSMP [9]

Answer:

You could use the polygon area formula OR here's an easier solution

We draw the lines DC and DE

Angle ADC = 120°

Triangle ADC is a 30 60 90 triangle

In such a triangle Line AE = hypotenuse * sq root (3) /2

Line AE = 3 * 0.8660254038 = 2.5980762114

Line DE = 1.5

Area of Triangle ADE = .5 * 1.5 * 2.5980762114 =

1.9485571586 square meters and entire area of Triangle

ABC = 6 * 1.9485571586

which equals 11.6913429513 square meters

Step-by-step explanation:

6 0

3 years ago

Charlie puts $50000 in a stock account, but it loses money at a rate of 20%

Alina [70]

Answer:

You dind't include the answer choices but it should look something like

$50000(.8)^t$

4 0

3 years ago

If G is the midpoint of FH find FG<br>fg=11x-7 gh= 3x+9

gavmur [86]

Solution:

we are given that

If G is the midpoint of FH, it mean that

$FG=GH$

we are also given that

$FG=11x-7 ,GH= 3x+9$

So we can write

$11x-7=3x+9\\
\\
11x-3x=7+9\\
\\
8x=16\\
\\
x=2$

So $FG=11x-7=11*\frac{1}{2}-7=11*2-7=15$

3 0

3 years ago

Classify each conic section and write its equations in standard form. Show work.

svp [43]

Answer:

The conic is ellipse of equation (x - 1)²/22 + (y + 4)²/44 = 1

Step-by-step explanation:

* Lets revise how to identify the type of the conic

- Rewrite the equation in the general form,

Ax² + Bxy + Cy² + Dx + Ey + F = 0

- Identify the values of A and C from the general form.

- If A and C are nonzero, have the same sign, and are not equal

to each other, then the graph is an ellipse.

- If A and C are equal and nonzero and have the same sign, then

the graph is a circle

- If A and C are nonzero and have opposite signs, and are not equal

then the graph is a hyperbola.

- If either A or C is zero, then the graph is a parabola

* Now lets solve the problem

The equation is 4x² + 2y² - 8x + 16y - 52 = 0

∴ A = 4 and C = 2 ⇒ same sign and different values

∴ The equation is ellipse

* The standard form of the ellipse is

(x - h)²/a² + (y - k)²/b² = 1

- Lets try to make this form from the general form

- Group terms that contain the same variable, and move the

constant to the opposite side of the equation

∴ (4x² - 8x) + (2y² + 16y) = 52

- Factorize the coefficients of the squared terms

∴ 4(x² - 2x) + 2(y² + 8y) = 52

- Complete the square for x and y

# To make completing square

- Divide the coefficient of x (or y) by 2 and then square the answer

- Add and subtract this square number and form the bracket of

the completing the square

# 2 ÷ 2 = 1 ⇒ (1)² = 1 ⇒ add and subtract 1

∴ 4[(x² - 2x + 1) - 1] = 4(x² - 2x + 1) - 4

- Rewrite as perfect squares ⇒ 4(x -1)² - 4

# 8 ÷ 2 = 4 ⇒ (4)² = 16 ⇒ add and subtract 16

∴ 2[(y² + 8y + 16) - 16] = 2(y² + 8y + 16)² - 32

- Rewrite as perfect squares ⇒ 2(y + 4)² - 32

∴ 4(x - 1)² - 4 + 2(y + 4)² - 32 = 52

∴ 4(x - 1)² - 4 + 2(y + 4)² = 32 + 4 + 52

∴ 4(x - 1)² + 2(y + 4)² = 88 ⇒ divide all terms by 88

∴ (x - 1)²/22 + (y + 4)²/44 = 1

8 0

3 years ago