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Illusion [34]
3 years ago
13

I’m having a hard time understanding substitution. Please help!

Mathematics
1 answer:
Vikentia [17]3 years ago
3 0

b_1=\frac{2A}{h}-b_2

Step-by-step explanation:

Given expression is;

A=\frac{h(b_1+b_2)}{2}

Solving for b_1

Multiplying both sides by 2

2*A=\frac{h(b_1+b_2)}{2}*2\\2A=h(b_1+b_2)

Dividing both sides by h

\frac{2A}{h}=\frac{h(b_1+b_2)}{h}\\\frac{2A}{h}=b_1+b_2

Subtracting b_2 from both sides

\frac{2A}{h}-b_2=b_1+b_2-b_2\\\frac{2A}{h}-b_2=b_1\\b_1=\frac{2A}{h}-b_2

b_1=\frac{2A}{h}-b_2

Keywords: division, subtraction

Learn more about subtraction at:

  • brainly.com/question/11145277
  • brainly.com/question/11150876

#LearnwithBrainly

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*I am assuming that the hexagons in all questions are regular and the triangle in (24) is equilateral*

(21)

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(22)

Similar to (21)

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(23)

For this case, we will have to consider the relation between the side and inradius of the hexagon. Since, a hexagon is basically a combination of six equilateral triangles, the inradius of the hexagon is basically the altitude of one of the six equilateral triangles. The relation between altitude of an equilateral triangle and its side is given by:

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(24)

Given is the inradius of an equilateral triangle.

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3 years ago
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Step-by-step explanation:

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Step-by-step explanation:

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Step-by-step explanation:

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Step-by-step explanation:

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