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3 years ago

12

A football team carried out a report to see the impact of stretching on preventing injury. Of the 60 footballers in the squad 48

stretch regularly. Of those who stretch, 8 got injured last year. There was a total of 17 injured players last year. The results can be presented in a frequency tree. What fraction of players are not stretching regularly?

1 answer:

lions [1.4K]3 years ago

6 0

Answer:

the fraction of players are not stretching regularly is 1 ÷ 5

Step-by-step explanation:

The computation of the fraction of the players not stretching regularly is as follows;

Given that

There are total number of 60 footballers

Out of which 48 strech regularly

So, the players who are not streching properly is

= 60 - 48

= 12

Now the fraction is

= 12 ÷ 60

= 1 ÷ 5

hence, the fraction of players are not stretching regularly is 1 ÷ 5

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vesna_86 [32]

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3 years ago

What is 3/8 plus 1/12

Delvig [45]

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3 years ago

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natka813 [3]

Answer:

C) 0.179

Step-by-step explanation:

Since the trials are independent, this is a binomial distribution:

<u>Recall:</u>

Binomial Distribution --> $P(k)={n\choose k}p^kq^{n-k}$
$P(k)$ denotes the probability of $k$ successes in $n$ independent trials
$p^k$ denotes the probability of success on each of $k$ trials
$q^{n-k}$ denotes the probability of failure on the remaining $n-k$ trials
${n\choose k}=\frac{n!}{(n-k)!k!}$ denotes all possible ways to choose $k$ things out of $n$ things

<u>Given:</u>

$n=10$
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<u>Calculate:</u>

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sattari [20]

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3 years ago