To simply this, you just divide the numerator and denominator by its GCF (Greatest common factor)
Factors of 18 : 1,2,3,6,9,18
Factors of 30 : 1,2,3,5,6,10,15,30
As you can see, the great common factors of 18 and 30 is 6.
So divide 18 by 6 and 30 by 6, and you get 3 and 5
Therefore, the simplest form is 3/5
Answer:
The correct option is 3.
Step-by-step explanation:
It is given that the oblique prism has a rectangular base with a width of 10 units and a length of 13 units. The top base extends 8 units to the right of the bottom base.
From the figure the height of prism is
![h=\sqrt{(17)^2-8^2}=\sqrt{225}=15](https://tex.z-dn.net/?f=h%3D%5Csqrt%7B%2817%29%5E2-8%5E2%7D%3D%5Csqrt%7B225%7D%3D15)
The height of prism is 15.
The volume of prism is
![V=(\text{base area })\times h](https://tex.z-dn.net/?f=V%3D%28%5Ctext%7Bbase%20area%20%7D%29%5Ctimes%20h)
![V=(10\times 13)\times 15](https://tex.z-dn.net/?f=V%3D%2810%5Ctimes%2013%29%5Ctimes%2015)
![V=1950](https://tex.z-dn.net/?f=V%3D1950)
The volume of prism is 1950 unit². Therefore the correct option is 3.
Answer:
Step-by-step explanation:
1 13/18
The 3 angles of a triangle add up to 180 degrees so:-
10x - 10 + 10x + 8 + 8x = 180
28x = 180 + 10 - 8
28x = 182
x = 6.5 (answer)
ANSWER
0.84375 mm
EXPLANATION
The velocity function is given by:
![v = 6t - 6 {t}^{2}](https://tex.z-dn.net/?f=v%20%3D%206t%20-%206%20%7Bt%7D%5E%7B2%7D%20)
To find the displacement function, we integrate:
![s = \int \: 6t - 6 {t}^{2}d t](https://tex.z-dn.net/?f=s%20%3D%20%20%5Cint%20%5C%3A%206t%20-%206%20%7Bt%7D%5E%7B2%7Dd%20t)
![s (t) = 3 {t}^{2} - 2 {t}^{3} + c](https://tex.z-dn.net/?f=s%20%28t%29%20%3D%203%20%7Bt%7D%5E%7B2%7D%20%20-%202%20%7Bt%7D%5E%7B3%7D%20%20%2B%20c)
The initial displacement is zero.
This implies that,
![3 {(0)}^{2} - 2 {(0)}^{3} + c = 0](https://tex.z-dn.net/?f=3%20%7B%280%29%7D%5E%7B2%7D%20%20-%202%20%7B%280%29%7D%5E%7B3%7D%20%20%2B%20c%20%3D%200)
![c = 0](https://tex.z-dn.net/?f=c%20%3D%200)
This gives us,
![s (t) = 3 {t}^{2} - 2 {t}^{3}](https://tex.z-dn.net/?f=s%20%28t%29%20%3D%203%20%7Bt%7D%5E%7B2%7D%20%20-%202%20%7Bt%7D%5E%7B3%7D%20)
After t=0.75s,
![s (0.75) = 3 {(0.75)}^{2} - 2 {(0.75)}^{3} + c](https://tex.z-dn.net/?f=s%20%280.75%29%20%3D%203%20%7B%280.75%29%7D%5E%7B2%7D%20%20-%202%20%7B%280.75%29%7D%5E%7B3%7D%20%20%2B%20c)
![s (0.75) = 0.84375](https://tex.z-dn.net/?f=s%20%280.75%29%20%3D%200.84375)