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N76 [4]
3 years ago
12

37 is ____ % of 148; 148 is ____ % of 37 fill in the blanks

Mathematics
1 answer:
soldier1979 [14.2K]3 years ago
4 0

37 is 25% of 148; 148 is 400% of 37

Step-by-step explanation:

Let us solve the questions one by one

"37 is ____ % of 148"

Let x be the percentage

Then

37 = x\%\ of\ 148\\37 = 148x\\x = \frac{37}{148}\\x = 0.25

to convert in percentage, multiplying by 100

= 25%

"148 is ____ % of 37"

Let y be the percentage

then

148 = y\%\ of\ 37\\148 = 37y\\y = \frac{148}{37}\\y = 4

To convert into percentage, multiplying by 100

= 400%

Hence,

37 is 25% of 148; 148 is 400% of 37

Keywords: Percentage, percent

Learn more about percentage at:

  • brainly.com/question/7932185
  • brainly.com/question/788903

#LearnwithBrainly

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use a calculator

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six angles of a heptagon measure 107, 139, 131, 110, 145. and 128. what is the measure of the seventh angle​
alexgriva [62]

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WHAT IS THE REMAINDER WHEN <img src="https://tex.z-dn.net/?f=32%5E%7B37%5E%7B32%7D%20%7D" id="TexFormula1" title="32^{37^{32} }"
Feliz [49]

Recall Euler's theorem: if \gcd(a,n) = 1, then

a^{\phi(n)} \equiv 1 \pmod n

where \phi is Euler's totient function.

We have \gcd(9,32) = 1 - in fact, \gcd(9,32^k)=1 for any k\in\Bbb N since 9=3^2 and 32=2^5 share no common divisors - as well as \phi(9) = 6.

Now,

37^{32} = (1 + 36)^{32} \\\\ ~~~~~~~~ = 1 + 36c_1 + 36^2c_2 + 36^3c_3+\cdots+36^{32}c_{32} \\\\ ~~~~~~~~ = 1 + 6 \left(6c_1 + 6^3c_2 + 6^5c_3 + \cdots + 6^{63}c_{32}\right) \\\\ \implies 32^{37^{32}} = 32^{1 + 6(\cdots)} =  32\cdot\left(32^{(\cdots)}\right)^6

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2 years ago
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2 years ago
In triangle KLM, if K is congruent to L, KL = 9x - 40, LM = 7x - 37, &amp; KM = 3x + 23, find x &amp; the measure of each angle.
Dennis_Churaev [7]

Answer: x = 15, ∠K = 45.7°, ∠L = 45.7°, ∠M = 88.6°

<u>Step-by-step explanation:</u>

Since ∠K ≅ ∠L, then ΔKLM is an isoceles triangle with base KL

 KM ≅ LM

3x + 23 = 7x - 37

       23 = 4x - 37

       60 = 4x

        15 = x

KM = LM = 3x + 23

               = 3(15) + 23

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KL = 9x - 40

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Next, draw a perpendicular bisector KN from K to KL. Thus, N is the midpoint of KL and ΔMNL is a right triangle.

  • Since N is the midpoint of KL and KL = 95, then NL = 47.5
  • Since ∠N is 90°, then NL is adjacent to ∠l and ML is the hypotenuse

Use trig to solve for ∠L (which equals ∠K):

cos ∠L = \frac{adjacent}{hypotenuse}

cos ∠L = \frac{47.5}{68}

      ∠L = cos⁻¹ (\frac{47.5}{68})

      ∠L = 45.7  

Triangle sum Theorem:

∠K + ∠L + ∠M = 180°    

45.7 + 45.7 + ∠M = 180

       91.4     + ∠M = 180

                      ∠M = 88.6

       

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