ANSWER
y=7
EXPLANATION
The horizontal asymptote of an exponential function

is y=c.
The given exponential function is

When we compare to

c=7, therefore the horizontal asymptote is y=7.
Probability is what the letter p indicates
The sum means addition
v + 3
25% as a fraction is 1/4 or 25/100 so as a decimal its 1/4 of 1 which is .25
In order to make a table, we sample some x values (whichever we want), and we compute the expression for those value. Each x value will yield a unique y value.
If you need this table to graph the function, you'll only need two points, since this is a line, and having two points you just need to connect them.
Here are some samples, feel free to make more if you need to:





So, we have the following table
