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Stels [109]
3 years ago
15

Type the correct answer in the box. Use a comma to separate the x- and y-coordinates of each point. The coordinates of the point

on the unit circle that corresponds to an angle of 0º are ( ). The coordinates of the point on the unit circle that corresponds to an angle of 90º are ( ).

Mathematics
1 answer:
MAVERICK [17]3 years ago
4 0

Answer:

On a unit circle, the point that corresponds to an angle of 0^{\circ} is at position (1, \, 0).

The point that corresponds to an angle of 90^{\circ} is at position (0, \, 1).

Step-by-step explanation:

On a cartesian plane, a unit circle is

  • a circle of radius 1,
  • centered at the origin (0, \, 0).

The circle crosses the x- and y-axis at four points:

  • (1, \, 0),
  • (0, \, 1),
  • (-1,\, 0), and
  • (0,\, -1).

Join a point on the circle with the origin using a segment. The "angle" here likely refers to the counter-clockwise angle between the positive x-axis and that segment.

When the angle is equal to 0^\circ, the segment overlaps with the positive x-axis. The point is on both the circle and the positive x-axis. Its coordinates would be (1, \, 0).

To locate the point with a 90^{\circ} angle, rotate the 0^\circ segment counter-clockwise by 90^{\circ}. The segment would land on the positive y-axis. In other words, the 90^{\circ}-point would be at the intersection of the positive y-axis and the circle. Its coordinates would be (0, \, 1).

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<h3>1. How many inches per minute does London's elevation change between 4 minutes and 8 minutes. </h3>

The question actually asks for the slope of the line that stands for the points (4,3) \ and \ (8,6) why? because the questions tells us that London's elevation changes between 4 minutes and 8 minutes here. Hence, to find the slope of this line we have to use the following formula:

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<em></em>

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The greater the absolute value of the slope of the line the faster London's elevation changes. Since this is a Piecewise function, we must analyze each period.

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→ Between 0 minutes and 4 minutes the function is constant, so there is no any change here.

→ Between 10 minutes and 14 minutes the function is constant, so there is no any change here.

→ Between 18 minutes and 22 minutes the function is constant, so there is no any change here.

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→ Between 4 minutes and 10 minutes the function has a positive slope, so there is change here.

In the previous item we calculated the slope between 4 and 8 minutes that is the same slope between 4 and 8 minutes and equals 0.75.

→ Between 14 minutes and 18 minutes the function has a positive slope, so there is change here.

Let's take two points here, say, (16,5) \ and \ (18,3)

m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}} \\ \\ But: \\ \\ P(x_{1},y_{1})=P(16,5) \\ P(x_{2},y_{2})=P(18,3) \\ \\ So: \\ \\ m=\frac{3-5}{18-16}=-1 in/min

As you can see, the absolute value here is 1 that is greater than 0.75.

<em>In conclusion, London's elevation changes the fastest between 14 and 18 minutes</em>

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