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aliina [53]
2 years ago
12

In the library at lenape elmentary school, there are 3/8 as, many fiction books as there are nonfiction books. There are 44 book

s in school library. How many booka are fiction books
Mathematics
1 answer:
N76 [4]2 years ago
5 0

Answer:

12 fiction books.

Step-by-step explanation:

Let b represent number of non-fiction books.

We have been given that in the library at Lenape elementary school, there are 3/8 as many fiction books as there are nonfiction books. So number of fiction books would be \frac{3}{8}x.

We are also told that there are 44 books in school library. We can represent this information in an equation as:

x+\frac{3}{8}x=44

Let us solve for x.

\frac{8x}{8}+\frac{3}{8}x=44

\frac{8x+3x}{8}=44

\frac{11x}{8}=44

\frac{11x}{8}\cdot \frac{8}{11}=44\cdot\frac{8}{11}

x=4\cdot 8

x=32

Therefore, there are 32 non fiction books in the library.

Number of fiction books would be \frac{3}{8}x\Rightarrow \frac{3}{8}*32=3*4=12

Therefore, there are 12 fiction books in the library.

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2. Solve the following system of equations. y = 5 + x 2x + 2y = 30
larisa86 [58]
X = 5

since we know y= 5 + x , plug this into y in the second equation.

2x + 2 (5 + x) = 30

distribute 2 into the 5 and x

2x + 10 + 2x = 30

combine like terms

4x + 10 = 30

subtract 10 from both sides

4x = 20

divide four by both sides to isolate the variable

x = 5
5 0
3 years ago
Read 2 more answers
The length of a rectangular football field, including both end zones, is 120 yards. The area of the field is 57,600 square feet.
egoroff_w [7]

Answer:

3a.False,the width is 53.33 yards

3b.true, the Length is 120 yards=360 feet

3c.True, width of the field is 160 feet.

3d. True,rea of the field is 6,400 square yards.

Step-by-step explanation:

Hello , I think I can help you with this

to solve this you must know the equivalence between feet and yard, which is

3 feet = 1 yard

Also, the area of  a rectangle is the product of its length by its width

Area=length *width

Step 1

convert 120 yards into feet using a rule of three

3 feet = 1 yard

x feet= 120 yards

3/1=x/120

x=(120*3)/1

x=360 feet

so

120 yards= 360 feet

Step 2

isolate the width from the area´s equation to find out it.

Area=57600 square feet

length=360 feet

Area=length *width

width=Area/length

Width=57600 square feet/360 feet

Width=160 feet

Step 3

convert 160 feet into yards

1 yard= 3 feet

x yard= 160 feet

1/3=x/160

x=(1*160)/3

x=53.33 yards

width=53.33 yards

the area is (square yards)

Area=120 yards*53.33 yards

Area=6400 square yards

Step 4

Answer the questions.

3a.False,the width is 53.33 yards

3b.true, the Length is 120 yards=360 feet

3c.True, width of the field is 160 feet.

3d. True,rea of the field is 6,400 square yards.

Have a nice day.

7 0
3 years ago
What is the missing statement for step 4?
Pepsi [2]
What is step 4??? What is the statement?
4 0
3 years ago
Find all solutions in the interval [0,2pi).<br><br> cos 2x + sqrt(2) sinx=1
kykrilka [37]
<span>cos 2x + sqrt(2) sinx=1
</span><span>
Note that: cos 2x = cos^2x - sin^2x = (1-sin^2x) - sin^2x = 1 - 2sin^2x.
So, when alternatively written, you have the following equation:

</span>- 2sin^2x + sqrt(2)sinx + 1 = 1
- 2sin^2x + sqrt(2)sinx = 0

Then, let z=sin(x). So you get,

- 2z^2 + sqrt(2)z = 0
z(- 2z + sqrt(2)) = 0

Either z=0, or - 2z + sqrt(2) = 0 --->  z=sqrt(2)/2.
Then, since z=0 or z=sqrt(2)/2, therefore sin(x)=0, or sin(x)=sqrt(2)/2.

Then, for you remains just to list the angles. (Let me know if this is not fair or if you got questions.)
6 0
3 years ago
1) A group of 100 students was surveyed about their interest in a new international studies program. interest was measured in te
liubo4ka [24]

Answer:

1) 0.30

2) 0.308

Step-by-step explanation:

1)

Interest   Frequency

High          30

Medium     40

Low            30

Total frequency=30+40+30=100.

The relative frequency of student with high interest can be computed by dividing the frequency of high interest to the total frequency.

R.f of high interest=30/100=0.30

2)

Monthly Commission Frequencies

600-800                  3

800-1000                  7

1000-1200                 11

1200-1400                 22

1400-1600                40

1600-1800                24

1800-2000                 9

2000-2200                 4

Total frequency=3+7+11+22+40+24+9+4=120

The relative frequency of earning 1600 or more computed by dividing the frequency of earning 1600 or more to the total frequency.

R.f of earning more than 1600=24+9+4/120=37/120=0.308

7 0
3 years ago
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