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SVETLANKA909090 [29]
3 years ago
12

Write the following ratios in simplest form.0.72m:96cm​

Mathematics
1 answer:
laila [671]3 years ago
7 0

Answer:

3:4

Step-by-step explanation:

0.72m=72cmm

so,72:96

72-36-18-9

96-48-24-12

9:12=3:4

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Write the addition or subtraction shown by the number line
Zigmanuir [339]
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4 0
3 years ago
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Locate 81/5,8.5,84/5,8.44 on a number line then write the numbers in order from least to greatest
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81/5 = 16.2
8.5
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6 0
3 years ago
Birth weights at a local hospital have a Normal distribution with a mean of 110 oz and a standard deviation of 15 oz. The propor
OLga [1]

Answer:

The proportion of infants with birth weights between 125 oz and 140 oz is 0.1359 = 13.59%.

Step-by-step explanation:

When the distribution is normal, we use the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this question, we have that:

\mu = 110, \sigma = 0.15

The proportion of infants with birth weights between 125 oz and 140 oz is

This is the pvalue of Z when X = 140 subtracted by the pvalue of Z when X = 125. So

X = 140

Z = \frac{X - \mu}{\sigma}

Z = \frac{140 - 110}{15}

Z = 2

Z = 2 has a pvalue of 0.9772

X = 125

Z = \frac{X - \mu}{\sigma}

Z = \frac{125 - 110}{15}

Z = 1

Z = 1 has a pvalue of 0.8413

0.9772 - 0.8413 = 0.1359

The proportion of infants with birth weights between 125 oz and 140 oz is 0.1359 = 13.59%.

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3 years ago
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3 years ago
What is the solution to the following system of equations? x+2y=2 x-2y=-2
Tcecarenko [31]
All in all you would get the answer x+y=1.
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3 years ago
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