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Montano1993 [528]
3 years ago
10

Gghjuyhyghggjtfdfhhhfgjfhhf​

Mathematics
2 answers:
netineya [11]3 years ago
6 0

Answer:

Step-by-step explanation:

was there a actual question ?

have a good day

topjm [15]3 years ago
3 0

Hello.

Have a beautiful and joyful day ahead.

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85 orders in 17 days = ? orders in 12 days
tamaranim1 [39]

Answer:

60

Step-by-step explanation:

Let the order be x

Solution

85/x= 17/12

1020=17x

1020/17=x

x=60

4 0
3 years ago
How many grams are in 844 mg
charle [14.2K]
The answer is 0.844 g
6 0
3 years ago
Can someone help me with this please?
AVprozaik [17]

Answer:

y=70°

z= 60°

w= 70°

Step-by-step explanation:

Since the two triangles are similar, we know that all of the corresponding angles must be the same.  On the triangle on the left, we can see that the angle formed between sides AB and AC is 60°.  This means that the same angle is formed at Z, which is in the same location on the triangle to the right.  From there, we can find the missing angle, W, from the difference of 180°.

180°-50°-60°=70°.

The same way we found Z, we can also find Y, since it has to be the same as W.

8 0
2 years ago
I need this answered please
MA_775_DIABLO [31]

I hope this helps

3x-y=13

step 1: add y to both sides

3x-y+Y=13+Y

3x=y+13

step 2: divide both sides by 3

3x/ 3 = y+13/3

x=1/3y+ 13/3

answer: x=1/3y+13/3

8 0
3 years ago
The proportion of U.S. births that result in a birth defect is approximately 1/33 according to the Centers for Disease Control a
Dafna11 [192]

Answer:

Probability that at least 490 do not result in birth defects = 0.1076

Step-by-step explanation:

Given - The proportion of U.S. births that result in a birth defect is approximately 1/33 according to the Centers for Disease Control and Prevention (CDC). A local hospital randomly selects five births and lets the random variable X count the number not resulting in a defect. Assume the births are independent.

To find - If 500 births were observed rather than only 5, what is the approximate probability that at least 490 do not result in birth defects

Proof -

Given that,

P(birth that result in a birth defect) = 1/33

P(birth that not result in a birth defect) = 1 - 1/33 = 32/33

Now,

Given that, n = 500

X = Number of birth that does not result in birth defects

Now,

P(X ≥ 490) = \sum\limits^{500}_{x=490} {^{500} C_{x} } (\frac{32}{33} )^{x} (\frac{1}{33} )^{500-x}

                 = {^{500} C_{490} } (\frac{32}{33} )^{490} (\frac{1}{33} )^{500-490}  + .......+ {^{500} C_{500} } (\frac{32}{33} )^{500} (\frac{1}{33} )^{500-500}

                = 0.04541 + ......+0.0000002079

                = 0.1076

⇒Probability that at least 490 do not result in birth defects = 0.1076

4 0
2 years ago
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