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3 years ago

Can someone help me with this and try to explain to me ?

Mathematics

1 answer:

Free_Kalibri [48]3 years ago

8 0

Remote interior angles are the two angles of a triangle that are not adjacent to the exterior angle which is drawn by extending one of the sides. So when you draw out your triangle, the remote interior angles are the two angles that are the furthest away from your exerior angle.

In this case your exterior angle would be <6

I hope this helps

~Ayden

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Martin finds a shirt on sale for 10% off at a department store. The original price was $20. Martin must also pay $8.5% sales tax

dem82 [27]

Answer:18.5 idk

Step-by-step explanation:

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4 years ago

Michael is putting 12 boxes in a storage shed. Each box is in the shape of a rectangular prism with dimensions 1.5 feet by 1.5 f

pishuonlain [190]

Answer:

Volume of room will be left after Michael stores the boxes 426 feet cube

Step-by-step explanation:

It is given that

Michael is putting 12 boxes in a storage shed.

Each box is in the shape of a rectangular prism with dimensions 1.5 feet by 1.5 feet by 2 feet.

If the storage shed has dimensions 6 feet by 10 feet by 8 feet,

To find the volume of one box

Volume = 1.5 x 1.5 x 2= 4.5 feet cube

Volume of 12 such box = 4.5 x 12 =54 feet cube

To find the volume of shed

Volume of Shed = 6 x 10 x 8 =480

To find remaining portion of shed

Volume of room will be left after Michael stores the boxes =volume of shed - volume of box

=480 - 54 = 426 feet cube

7 0

3 years ago

Find the value of the derivative (if it exists) at the indicated extremum. (If an answer does not exist, enter DNE.)

Liono4ka [1.6K]

Answer:

The answer is "0".

Step-by-step explanation:

Please find the correct question in the attached file.

Given value:

$\to f(x) =\frac{x^2}{x^2+5}\\\\$

Formula:

$\bold{\frac{d}{dx} \frac{u}{v} = \frac{ v \frac{du}{dx} - u \frac{dv}{dx}}{v^2}}$

$\to f'(x) =\frac{(x^2+5) 2x -2x^3 (2x)}{(x^2+5)^2}\\\\\to f'(0) =\frac{(0^2+5)2(0) -4(0)^4}{(0^2+5)^2}\\\\\to f'(0) =\frac{(0)(5) -2(0)}{(5)^2}\\\\\to f'(0) =\frac{0 - 0}{(5)^2}\\\\\to f'(0) =\frac{0}{25}\\\\\to f'(0) = 0$

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3 years ago

A 0.30 kg bird flies in a horizontal curve of radius 20 m at 15 m/s. The force exerted by the air on the bird is about

monitta

Answer:

<h2>b) 3.48 N approx.</h2>

Step-by-step explanation:

The bird will experience a centripetal force, this is the force exerted on a body that moves through a curve path.

$F_c = \frac{mv^2}{r}$

Fc=centripetal force

m=mass

v=velocity

r=radius

Step one:

given data

mass of bird m=0.3kg

the radius of curve r= 20m

velocity v= 15 m/s

Substituting we have

$F_c = \frac{0.3*15^2}{20}\\\\F_c= \frac{0.3*225}{20}\\\\ F_c=\frac{67.5}{20}\\\\F_c=3.37N$

The force is 3.37N

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3 years ago

A company in Maryland has developed a device that can be attached to car engines, which it believes will increase the miles per

HACTEHA [7]

Answer:

About 0.72

Step-by-step explanation:

Given the data:

With device : 22.6, 23.4, 28.4, 29, 29.3, 20.0

Without device :26.9, 24.4, 20.8, 20.8, 20.2, 26.0, 28.1, 25.6

Using calculator:

With device data:

Sample size (n1) = 6

Degree of freedom (df1) = 6 - 1 = 5

Mean(m1) = 25.45

Variance (s²1) = 15.631

Without device data:

Sample size (n2) = 8

Degree of freedom (df2) = n - 1 = 7

Mean (m2) = 24.1

Variance (s²2) = 9.54

s²t = ((df1/(df1 + df2)) * s²1) + ((df2/(df1 + df2)) * s²2)

s²t = ((5/(5+7)*15.63) + ((7/(5+7))*9.54)

= ((5/12) * 15.63) + ((7/12) * 9.54) = 12.0775

s²m1 = s²t/n1 = 12.0775/6 = 2.0123

s²m2 = s²t/n2 = 12.0775/8 = 1.511

T - statistic :

Tstat = (m1 - m2)/√(s²m1 + s²m2)

Tstat = (25.45 - 24.10) / √(2.0123 + 1.511)

Tstat= 1.350/√3.5233

Tstat = 1.350 / 1.8770455

Tstat = 0.7192153 = 0.72

8 0

3 years ago