Answer:
252 menu
Step-by-step explanation:
Total number courses, n = 10
The largest number of menu the chef can plan using his 10 main courses.
There are various combinations of menu obtainable from the available courses :
Ranging from :
nC0 to nCn
The largest number of menu he can plan is the highest output obtainable between :
10C0 to 10C10
10C0 = 1
10C1 = 10
10C2 = 45
10C3 = 120
10C4 = 210
10C5 = 252
10C6 = 210
10C7 = 120
10C8 = 45
10C9 = 10
10C10 = 1
Hence, the largest number of menu he can plan using his 10 main courses is 252
Answer:
The correct answer is option C.
The mid point of the line segment.
Step-by-step explanation:
the perpendicular line segment construction twice using paper folding
we have to find the mid point of the given line segment.
We get the midpoint easily when fold the paper correctly
Therefore the correct answer is option C.
The mid point of the line segment.
Answer:
D) The very last one
Step-by-step explanation:
n + 6 < 4
n < -2
< means it's an open circle and goes in the LEFT direction
Answer:
Hold on i got it
Step-by-step explanation:
The answer is 72 is you need me to explain I’d be glad to help.
