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Mathematics

2 answers:

Dahasolnce [82]3 years ago

8 0

${ \sf{ factorise \: \: { \underline{ \green { \tt{ {x}^{2} (x + 2) - x(x + 2) - 12(x + 2)}}}}}}$

${ \sf{ \blue{ \:taking \: (x + 2) \: common}}} \\ \\{ \dashrightarrow { \sf{ \green{(x + 2)( {x}^{2} - x - 12)}}}}$

${ \dashrightarrow{ \sf{ \green{(x + 2)( {x}^{2} - (4x - 3x) - 12)}}}} \\ \\ { \dashrightarrow{ \sf{ \green{(x + 2)( {x}^{2} - 4x + 3x - 12)}}}}$

${ \dashrightarrow{ \green{ \sf{(x + 2)(x(x - 4) + 3(x - 4))}}}} \\ \\ { \dashrightarrow{ \underline{ \boxed{ \green{ \sf{(x + 2)(x + 3)(x - 4)}}}}}}$

Goryan [66]3 years ago

6 0

Answer:

(x + 2)(x - 4)(x + 3)

Step-by-step explanation:

x²(x + 2) ‐ x(x + 2) ‐ 12(x + 2) =
(x + 2)(x² - x - 12) =
(x + 2)(x² - 4x + 3x - 12) =
(x + 2)(x - 4)(x + 3)

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