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postnew [5]
3 years ago
11

william is trying to solve the last problem of his math homework: 5/8 divided by 2/3. which of the following will give him the c

orrect answer
Mathematics
1 answer:
guajiro [1.7K]3 years ago
7 0

Answer:

15/16

Step-by-step explanation:

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What is the result of increasing 50 by 30%?
kogti [31]

Answer:

50 increased by 30% is 65

Step-by-step explanation:

'Percent (%)' means 'out of one hundred':

p% = p 'out of one hundred',

p% is read p 'percent',

p% = p/100 = p ÷ 100.

30% = 30/100 = 30 ÷ 100 = 0.3.

100% = 100/100 = 100 ÷ 100 = 1.

Percentage increase = 30% × 50

New value = 50 + Percentage increase

Calculate

New value =

50 + Percentage increase =

50 + (30% × 50) =

50 + 30% × 50 =

(1 + 30%) × 50 =

(100% + 30%) × 50 =

130% × 50 =

130 ÷ 100 × 50 =

130 × 50 ÷ 100 =

6,500 ÷ 100 =

65

Or just find 30% of 50 (15) and add that

8 0
2 years ago
How do we solve for x
Verizon [17]

Answer:

Use Cross product Or Multiply both sides by 6 to get x alone

x/6 = 4/5

Multiplying 6 on both sides

we have

x=4/5 x 6

x=24/5 = 4.8

3 0
3 years ago
4. An airplane at T(80,20) needs to fly to both U(20,60) and V(110,85). What is the shortest possible distance for the trip?
damaskus [11]
The distance formula for two points in a plane is 
D=sqrt( (x1-x2)^2 + (y1-y2)^2 ) 
 From T to U
 D= sqrt((80-20)^2 + (20-60)^2) = 72.11 
 Then flying from U to V
 D= sqrt((20-110)^2 + (60-85)^2) = 93.4 
 So T to U to V = 72.11+93.4 = 165.5 
 BUT checking also T to V to U
 From T to V
 D= sqrt((80-110)^2 + (20-85)^2) = 71.6
 Then from V to U
 D= sqrt((110-20)^2 + (85-60)^2) = 93.4 
 So from T to V to U = 165
 Pretty much the same both directions
 So yes the answer is A
4 0
3 years ago
A factory has three machines that all manufacture the same engine part. From long historical records the company has determined
Alex Ar [27]

Answer:

Step-by-step explanation:

P(D/M₁) = .04 ( probability of defect from a 1 st machine )

P(D/M₂) = .06

P(D/M₃) = .01

P( M₁ )= .3 ( probability of manufacture from 1 st machine )

P(M₂) = .2

P(M₃)= .5

P( M₁/D) ( Probability of manufacture from 1 st machine , given it is defective )

= P( M₁ )xP(D/M₁) / [P( M₁ )xP(D/M₁) +P( M₂ )xP(D/M₂)+P( M₃ )xP(D/M₃)]

= .3 x .06 / .3 x .06 + .2 x .06 + .5 x .01

= .018 / .035

= 18/35

3 0
3 years ago
Plot ΔABC on graph paper with points A(3,3), B(1,1), and C(6,1). Reflect ΔABC by multiplying the y-coordinates of the vertices b
MAXImum [283]

Answer:

First one would be D (( A'(-3,-6), B'(-5,-4), C'(0,-4) ))

The second would be D (( A'(-15,8), B'(-4,5), C'(-9,6) )) as well

6 0
3 years ago
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