Question

3a+2b=8 \displaystyle a = 6b + 6 a=6b+6

Answer 1

First, let's write it like this:
$3a+2b=8$
Subtract $2b$ from both sides.
$3a+2b-2b=8-2b$
$3a=8-2b$
Divide both sides by 3.
$\frac{3a}{3}=\frac{8-2b}{3}$
$a=\frac{8-2b}{3}$

Now that we know what's the value of $a$, let's find the value of $b$
$3\cdot \frac{8-2b}{3}+2b=8$
Let's take the first part.
$3\cdot \frac{8-2b}{3}$
Multiply the fractions.
$=\frac{\left(8-2b\right)\cdot \:3}{3}$
Cancel the common factor, which is 3.
$=8-2b$
We would be left with.
$=8-2b+2b$
Add like terms.
$=8$
We would be left with.
$8=8$
Subtract 8 from both sides.
$8-8=8-8$
$0=0$

This tells us that $b$ can be any number. 

Let me know if you need any help!
Thanks!
-TetraFish