Step-by-step answer:
Given:
mean, mu = 200 m
standard deviation, sigma = 30 m
sample size, N = 5
Maximum deviation for no damage, D = 100 m
Solution:
Z-score for maximum deviation
= (D-mu)/sigma
= (100-200)/30
= -10/3
From normal distribution tables, the probability of right tail with
Z= - 10/3
is 0.9995709, which represents the probability that the parachute will open at 100m or more.
Thus, by the multiplication rule, the probability that all five parachutes will ALL open at 100m or more is the product of the individual probabilities, i.e.
P(all five safe) = 0.9995709^5 = 0.9978565
So there is an approximately 1-0.9978565 = 0.214% probability that at least one of the five parachutes will open below 100m
Answer:
In 2 2/15 hours, the prices will be same
Step-by-step explanation:
I hope this helps :)
The solution of such a system is the ordered pair that is a solution to both equations. To solve a system of linear equationsgraphically we graph both equations in the same coordinate system. The solution to the system will be in the point where the two lines intersect.
1.35/12=0.1125, rounds to about $0.11.
Each pencil was about $0.11.
