Question

LAST ONE, ON A TIMER. Find the zeros of the function and write in a + bi form. -(x+1)^2-4=0

Answer 1

Answer:

• Option D

Step-by-step explanation:

• -(x+1)²- 4 = 0
• (x+1)² =  - 4
• x + 1 = ± √-4
• x = -1 ± 2i

Correct choice is D

Answer 2

Answer:

D

Step-by-step explanation:

Given

- (x + 1)² - 4 = 0 ( add 4 to both sides )

- (x + 1)² = 4 ( multiply both sides by - 1 )

(x + 1)² = - 4 ( take the square root of both sides )

x + 1 = ± $\sqrt{-4}$ = ± 2i ( subtract 1 from both sides )

x = - 1 ± 2i , then

x = - 1 + 2i, x = - 1 - 2i → D