Answer:
The answer is option 1.
Step-by-step explanation:
You have to apply Gradient formula :
Please help asap !
1 answer:
You might be interested in
I hope this helps you
$\sec x=\frac1{\cos x}$
$\therefore \cot^2x\cdot\sec^2x= \frac{\cos^2x}{\sin^2x}\frac{1}{\cos^2x}=\frac{1}{\sin^2x}$