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ollegr [7]
3 years ago
14

ANSWER ASAP PLEASE!!

Mathematics
2 answers:
Sidana [21]3 years ago
5 0

Answer:

A,C, E,F

Step-by-step explanation:

just took the test

aliya0001 [1]3 years ago
3 0

Answer:

Clayton could use the relationship (x,y)→ (y,x) to find the points of the image

C’ will remain in the same location as C because it is on the line of reflection

The image and the pre-image will be congruent triangles

The image and pre-image will not have the same orientation because reflections flip figures

Step-by-step explanation:

<u><em>Verify each statement</em></u>

case A) Clayton could use the relationship (x,y)→ (y,x) to find the points of the image

The statement is true

we know that

The rule of the reflection of a point across the line y=x is equal to

(x,y)→ (y,x)

case B) Clayton could negate both the x and y values in the points to find the points of the image

The statement is false

case C) C’ will remain in the same location as C because it is on the line of reflection

The statement is true

If a point is on the line of reflection (y=x), then the point remain in the same location because the x and y coordinates are equal

case D) C’ will move because all points move in a reflection

The statement is false

Because C' is on the line of reflection (y=x), then the point remain in the same location

case E) The image and the pre-image will be congruent triangles

The statement is true

Because the reflection not change the length sides of the triangle or the measure of its internal angles. Reflection changes only the orientation of the figure

case F) The image and pre-image will not have the same orientation because reflections flip figures

The statement is true

Because in a reflection across the line y=x, the x coordinate of the pre-image becomes the y-coordinate of the image and the y-coordinate of the pre-image becomes the x-coordinate of the image

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determine the value of x for which r parallels s. then find the measure of angle 1 and the measure of angle 2measure angle 1= 50
Maslowich

According to the picture, angles 1 and 2 have the same measure because they are corresponding angles. Make equal both expressions for 1 and 2 and find x.

\begin{gathered} 50-2x=110-42x \\ 42x-2x=110-50 \\ 40x=60 \\ x=\frac{60}{40} \\ x=\frac{3}{2} \end{gathered}

x is 3/2. Replace this value in both expression to find the measure of each angle.

\begin{gathered} \measuredangle1=50-2x \\ \measuredangle1=50-2(\frac{3}{2}) \\ \measuredangle1=50-3 \\ \measuredangle1=47 \\ \measuredangle2=110-42x \\ \measuredangle2=110-42(\frac{3}{2}) \\ \measuredangle2=110-63 \\ \measuredangle2=47 \end{gathered}

The measure of these angles is 47°

7 0
1 year ago
One number is 5 more than another number. their sum is −15 . what are the numbers?
Aliun [14]
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6 0
3 years ago
Complete the square to the problem X^2+6x-16=0
marishachu [46]

Answer:

<h2>x = -8 or x = 2</h2>

Step-by-step explanation:

(a+b)^2=a^2+2ab+b^2\qquad(*)\\\\-------------------------------\\\\x^2+6x-16=0\qquad\text{add 16 to both sides}\\\\x^2+6x=16\\\\x^2+2(x)(3)=16\qquad\text{add}\ 3^2\ \text{to both sides}\\\\\underbrace{x^2+2(x)(3)+3^2}_{(*)}=16+3^2\\\\(x+3)^2=16+9\\\\(x+3)^2=25\Rightarrow x+3=\pm\sqrt{25}\\\\x+3=-5\ \vee\ x+3=5\qquad\text{subtract 3 from both sides}\\\\\boxed{x=-8\ \vee\ x=2}

3 0
3 years ago
The ratio of girls to boys in Liza’s classroom is 5 to 4. How many girls are in her classroom if there is a total of 27 students
prisoha [69]

Answer:

Number of girls =  15

Step-by-step explanation:

girls : boys = 5 : 4

Number of girls = 5x

Number of boys = 4x

Total students = 27

5x +4x = 27

9x = 27

x = 27/9

x = 3

Number of girls = 5x = 5*3 = 15

7 0
2 years ago
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