Answer:
Step-by-step explanation:
Given that a box contains 45 light bulbs, of which 36 are good and the other 9 are defective.
Probability for any one to be defective as of now is 
a) 
b) After I draw we have 35 good ones and 9 defective
P(F/E) =
c) P(G/EF)
This is the probability for iii bulb to be good given I and II are goog.
Once I and ii are good we have 43 bulbs with 34 good ones

Answer:
what
Step-by-step explanation:
sure?
Answer:
#7 is x = 51
#8 is x = 9
Step-by-step explanation:
#7 walk-through
35 + 2x + 16 + 4x + 3 = 360
35 + 16 + 3 + 2x + 4x = 360
54 + 6x = 360
6x = 306
x = 51
#8 walk-through
6x + 2 = 56
6x = 54
x = 9
Answer:
F = -44. I have attached the work too