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larisa [96]
2 years ago
5

Suppose that a box contains 45 light bulbs, of which 36 are good and the other 9 are defective. Consider randomly selecting thre

e bulbs without replacement. Let E denote the event that the first bulb selected is good, F be the event that the second bulb is good, and G represent the event that the third bulb selected is good.
(a)

What is

P(E)?


(b)

What is

P(F|E)?

(Round your answer to three decimal places.)


(c)

What is

P(G|E ∩ F)?

(Round your answer to three decimal places.)


(d)

What is the probability that all three selected bulbs are good? (Round your answer to three decimal places.)
Mathematics
1 answer:
Andrew [12]2 years ago
5 0

Answer:

Step-by-step explanation:

Given that a box contains 45 light bulbs, of which 36 are good and the other 9 are defective.

Probability for any one to be defective as of now is \frac{36}{45} =0.80

a) P(E) = 0.80

b) After I draw we have 35 good ones and 9 defective

P(F/E) =\frac{35}{44} \\=0.796

c) P(G/EF)

This is the probability for iii bulb to be good given I and II are goog.

Once I and ii are good we have 43 bulbs with 34 good ones

P(G/EF) =\frac{34}{43} \\=0.7907

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1/8+6/8=7/8

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When a number is divided by -3, the result is 12 more than the number what is the number?
olga55 [171]
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go from inside out.

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Vadim26 [7]

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Explanation:

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We need to determine whether the equation y=2x+2 is a function.

To determine the equation is a function, let us substitute the coordinates in the equation and check whether it satisfies the equation.

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