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3 years ago

5(f + 4) = 4(f - 6) NEED HELP ASAP, ALSO PLEASE HELP ME DO IT STEP BY STEP!!

Mathematics

2 answers:

stepan [7]3 years ago

8 0

Answer:

F = -44. I have attached the work too

arlik [135]3 years ago

5 0

Answer:

Step-by-step explanation:

5(f+4)=4(f-6)

5f+20=4f-24 : distribute the 5 and 4 to the equations in parentheses by multiplying

f+20=-24 : subtract the 4f from the right side and bring it to the left side where the 5f is

f=-44 : subtract the 20 from the left side and add it to the -24

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PLEASE HELP SO I CAN PASS MY TEST

Brums [2.3K]

Answer:

Step-by-step explanation:

The first thing to do would be to find how many 1/4 cups are in the 1 cup. Divide 1 by 1/4 and you'd get 4.

Just multiply 2 1/2 by 4 and you get 10

8 0

3 years ago

Read 2 more answers

Find the value of x.

Sholpan [36]

Answer:

x = √21.

Step-by-step explanation:

Triangles ADB and BCD are similar.

So their corresponding sides are in the same ratio:

x / 7 = 3 / x

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3 years ago

Solve for t<br><br> - 7/4 = 2/5 (t)<br><br> t=

Lena [83]

-7/4:-1.75
2/5:0.4
-1.75=0.4t
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Hope I helped you well, have a victorious day!

4 0

2 years ago

This number is in scientific notation. 2. 4 × 10-4 Convert the number into standard notation. What is the value? 2. 4 × 10-4 =.

Dimas [21]

2.4x10^-4 = 0.00024

7 0

2 years ago

The rectangle below has an area of 6n^4+20n^3+14n^26n 4 +20n 3 +14n 2 6, n, start superscript, 4, end superscript, plus, 20, n,

Sindrei [870]

Given:

Area of rectangle = $6n^4+20n^3+14n^2$

Width of the rectangle is equal to the greatest common monomial factor of $6n^4, 20n^3,14n^2$ .

To find:

Length and width of the rectangle.

Solution:

Width of the rectangle is equal to the greatest common monomial factor of $6n^4, 20n^3,14n^2$ is

$6n^4=2\times 3\times n\times n\times n\times n$

$20n^3=2\times 2\times 5\times n\times n\times n$

$14n^2=2\times 7\times n\times n$

Now,

$GCF(6n^4, 20n^3,14n^2)=2\times n\times n=2n^2$

So, width of the rectangle is $2n^2$ .

Area of rectangle is

$Area=6n^4+20n^3+14n^2$

Taking out GCF, we get

$Area=2n^2(3n^2+10n+7)$

We know that, area of a rectangle is the product of its length and width.

Since, width of the rectangle is $2n^2$ , therefore length of the rectangle is $(3n^2+10n+7)$ .

5 0

3 years ago