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Naya [18.7K]
3 years ago
6

The gear ratio of two gears is the ratio of the number of teeth of the larger gear to the number of teeth of the smaller gear. I

n a set of three gears, the ratio of Gear A to Gear B is equal to the ratio of Gear B to Gear C. Gear A has 36 teeth and Gear C had 16 teeth. How many teeth does Gear B have?
Mathematics
1 answer:
VLD [36.1K]3 years ago
6 0

Answer:

24 gear.

Step-by-step explanation:

It is given that Gear A:Gear B=Gear B:Gear C.

\dfrac{Gear A}{Gear B}=\dfrac{Gear B}{Gear C}

Gear A = 36 teeth

Gear C = 16 teeth

Let gear B have x teeth.

\dfrac{36}{x}=\dfrac{x}{16}

On cross multiplication we get

36\times 16=x\times x

576=x^2

Taking square root on both sides.

24=x

Therefore, gear B have 24 teeth.

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If the diameter of a circle is 20mm, what is the area of the circle?
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Can u show me how to solve this problem 0.11 times 0.91
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0.1001

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3 years ago
Conjunction and disconjuction​
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When two statements are connected with an 'and,' you have a conjunction.

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7 0
2 years ago
Given: mMEJ=30°,<br> mMFJ= 50°<br> Find: mKL, mMJ
makvit [3.9K]

Applying the angles of intersecting secants theorem, the measures of the arcs are:

m(KL) = 20°; m(MJ) = 80°.

<h3>What is the Angles Intersecting Secants Theorem?</h3>

When two secants intersect and form an angle outside the circle, the measure of the angle formed is half the positive difference of the measures of the intercepted arcs.

Given the following:

  • m∠MEJ = 30°
  • m∠MFJ = 50°

m∠MEJ = 1/2(MJ - KL)

30 = 1/2(MJ - KL)

60 = MJ - KL

KL = MJ - 60

m∠MFJ = 1/2(MJ + KL)

50 = 1/2(MJ + MJ - 60)

100 = 2MJ - 60

2MJ = 100 + 60

2MJ = 160

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MJ = 80°

KL = MJ - 60 = 80 - 60

KL = 20°

Thus, applying the angles of intersecting secants theorem, the measures of the arcs are:

m(KL) = 20°; m(MJ) = 80°.

Learn more about angles of intersecting secants theorem on:

brainly.com/question/1626547

4 0
2 years ago
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