Question

What is the inverse of the given relation? Y=7x^2+4

Answer 1

follow these steps:

1) y-4=7x^2

2) (y-4)/7 = x^2

$x = \sqrt{ \frac{y - 4}{7} }$

so you must inverse x and y names:

${f}^{ - 1} (x) = \sqrt{ \frac{x - 4}{7} }$