Let each side perpendicular to the wall be x
The parallel to the wall will be 320-2x
the area will be:
A(x)=x(320-2x)
A(x)=320x-2x^2
This is a quadratic with a =-2 and b=320
Maximum area will occur where x=-b/2a
=-320/(-2*2)
=80 ft
thus the width will be 80 ft and the length will be:
length=320-2*80=160 ft
B. Lost 850 ft
800-450= 350
1200-350=850
I hope I helped :D
Answer:
General term
=
n
t
h
t
e
r
m
=
a
n
=
5
n
+
2
Explanation:
Here,
7
,
12
,
17
,
22
,
27
,
...
is an Arithmetic Sequence.
The
,
n
t
h
term of Arithmetic Sequence is :
a
n
=
a
1
+
(
n
−
1
)
d
,
w
h
e
r
e
,
a
1
=
first term and
d
=
common difference
We have,
a
1
=
7
and
d
=
12
−
7
=
17
−
12
=
...
=
5
So,
a
n
=
7
+
(
n
−
1
)
⋅
5
a
n
=
7
+
5
n
−
5
a
n
=
5
n
+
2
Hence,
General term
=
n
t
h
t
e
r
m
=
a
n
=
5
n
+
2
Step-by-step explanation:
Answer:
Maximum 3 numbers. Minimum 1 number.
Step-by-step explanation:
Well, let us look at the case when 3 numbers are greater than 30. Let us take numbers as 1, 2, 3 and 114 and find their mean which is (1+2+3+114)/4=30.
Now let us look at the case in which 2 numbers greater than 30. Let us take numbers 28, 29, 31 and 32 and find their mean which is (28+29+31+32)/4=30.
Now let us look at the case in which 1 number greater than 30. Let us take numbers 27, 28, 29 and 36 and find their mean which is (27+28+29+36)/4=30.
So it can be concluded that maximum 3 numbers and minimum 1 number are greater than 30.
