Match the situations to the simulations that model them using the numbers 0 through 9. Tiles Estimate the probability of drawing
1 yellow marble from a box that contains 20 red marbles, 30 blue marbles, 10 green marbles, and 40 yellow marbles. Use the number 0 to represent the yellow marbles and 1 through 9 to represent the other marbles. Estimate the probability of drawing 1 yellow marble from a box that contains 60 red marbles, 120 blue marbles, 30 green marbles, and 90 yellow marbles. Use the numbers 0 through 2 to represent the yellow marbles and 3 through 9 to represent the other marbles. Estimate the probability of drawing 1 yellow marble from a box that contains 30 red marbles, 40 blue marbles, 10 green marbles, and 20 yellow marbles. Use the numbers 0 through 4 to represent the yellow marbles and 5 through 9 to represent the other marbles. Estimate the probability of drawing 1 yellow marble from a box that contains 30 red marbles, 40 blue marbles, 20 green marbles, and 10 yellow marbles. Use the numbers 0 through 3 to represent the yellow marbles and 4 through 9 to represent the other marbles. Estimate the probability of drawing 1 yellow marble from a box that contains 16 red marbles, 32 blue marbles, 32 green marbles, and 80 yellow marbles. Estimate the probability of drawing 1 yellow marble from a box that contains 90 red marbles, 120 blue marbles, 30 green marbles, and 60 yellow marbles.
Question 1) <span>Estimate
the probability of drawing 1 yellow marble from a box that contains 20
red marbles, 30 blue marbles, 10 green marbles, and 40 yellow marbles.
</span>
<span>Answer: 2/5 = 0.4 </span>
<span>Explanation: </span>
<span>1) Probability = number of positive events / number of possible events </span>
<span>Question 2. Estimate the probability of drawing 1
yellow marble from a box that contains 60 red marbles, 120 blue marbles,
30 green marbles, and 90 yellow marbles. </span>
Answer: 3/10 = 0.3
Explanation:
1) Probability = number of positive events / number of possible events
2) number of positive events = number of yellow marbles = 90
3) number of possible events = number of marbles = 60 + 120 + 30 + 90 = 300
4) probability = 90 / 300 = 3/10 = 0.3
Question 3. Estimate the probability of drawing 1 yellow marble from a box
that contains 30 red marbles, 40 blue marbles, 10 green marbles, and 20
yellow marbles.
Answer: 2/9 = 0.22
Explanation:
<span>1) Probability = number of positive events / number of possible events </span>
2) number of positive events = number of yellow marbles = 20
3) number of possible events = number of marbles = 90
4) probability = 20 / 90 = 2/9 = 0.22
Question 4. Estimate the
probability of drawing 1 yellow marble from a box that contains 30 red
marbles, 40 blue marbles, 20 green marbles, and 10 yellow marbles.
Answer: 1/10 = 0.1
Explanation:
1) Probability = number of positive events / number of possible events
2) number of positive events = number of yellow marbles = 10
3) number of possible events = number of marbles = 30 + 40 + 20 + 10 = 100
4) probability = 10 / 100 = 1/10 = 0.1
Question 5. Estimate the probability of drawing 1
yellow marble from a box that contains 16 red marbles, 32 blue marbles,
32 green marbles, and 80 yellow marbles.
Answer: 1/2 = 0.5
Explanation:
<span>1) Probability = number of positive events / number of possible events </span>
2) number of positive events = number of yellow marbles = 80
3) number of possible events = number of marbles = 16 + 32 + 32 + 80 = 160
4) probability = 80 / 160 = 1/2 = 0.5
Question 6. Estimate the probability of
drawing 1 yellow marble from a box that contains 90 red marbles, 120
blue marbles, 30 green marbles, and 60 yellow marbles.
<span>Answer: 1/5 = 0.2 </span><span> </span><span> </span><span>Explanation: </span><span> </span><span> </span><span>1) Probability = number of positive events / number of possible events</span>
2) number of positive events = number of yellow marbles = 60
3) number of possible events = number of marbles = 90 + 120 + 30 + 60 = 300 <span />
The answer is B. The problem involves partial sums, thus the presence of sigma for easier coverage. The number above the sigma is the number where the process stops, while the number below is the starting value of the unknown value in the equation.
