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natali 33 [55]
3 years ago
15

How do you sovle 10-3x-1≥6x

Mathematics
1 answer:
KATRIN_1 [288]3 years ago
3 0
You should move the 3x over to the 6x, making the equation
10 - 1 \geqslant 9x
you then divide the 9 on both sides, making 9/9x become 1x or just x, and the other 9/9, which equals 1. overall, your final equation should be
x  \leqslant  1
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