3 years ago

How do you sovle 10-3x-1≥6x

1 answer:

3 0

You should move the 3x over to the 6x, making the equation
$10 - 1 \geqslant 9x$
you then divide the 9 on both sides, making 9/9x become 1x or just x, and the other 9/9, which equals 1. overall, your final equation should be
$x \leqslant 1$

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