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Pie
3 years ago
13

2. Helen can type 120 words in 4 minutes. How many words can she type

Mathematics
2 answers:
erastovalidia [21]3 years ago
6 0

Answer:

The Answer is 180 words

lara31 [8.8K]3 years ago
6 0
I think it is d because then it would be q constant rate of change of 30
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Two over five, one over four, three over eight
jek_recluse [69]

Answer:

I would like to solve your problem but plz comment the equation

Step-by-step explanation:

2/5×1/4×3/8 is 6/160

7 0
3 years ago
Read 2 more answers
Bob bought a bike for $250 and repaired it . He can now sell the bike for $300. What is the percent increase in the value bike ?
alexgriva [62]

Answer:20%

Step-by-step explanation:

250*20%=50

50+250=300

7 0
3 years ago
What is the third angle of a triangle if the other two are (3x-20)° and (4x+10)°​
Karolina [17]

Answer:

The other angle is 190-7x.

Step-by-step explanation:

Angles in a triangle add up to 180 degrees.

Let A be the third angle.

A + (3x-20) + (4x+10) = 180

A = 180 - (3x - 20) - (4x + 10) = 190 - 7x

8 0
3 years ago
I need help hdbcjsjfnfnfjfjffdbbfdncndnc
lbvjy [14]
\frac{3}{15k+30} : \frac{6k}{5k^2+30k+40} = \frac{3}{15(k+2)} . \frac{5(k+2)(k+4)}{6k} = \frac{k+4}{6k}
8 0
3 years ago
A recent survey based on a random sample of n=470 voters, predicted that independent candidate for the mayoral election will get
julsineya [31]

I have an expression

\sigma = \sqrt{p(1-p)/n}

floating around in my head; let's see if it makes sense.

The variance of binary valued random variable b that comes up 1 with probability p (so has mean p) is

E( (b-p)^2 ) =  (-p)^2(1-p) + (1-p)^2p = p(1-p)

That's for an individual sample. For the observed average we divide by n, and for the standard deviation we take the square root:

\sigma = \sqrt{p(1-p)/n}

Plugging in the numbers,

\sigma = \sqrt{.24(1-.24)/490} = 0.019 = 1.9\%

One standard deviation of the average is almost 2% so a 27% outcome was 3/1.9 = 1.6 standard deviations from the mean, corresponding to a two sided probability of a bit bigger than 10% of happening by chance.

So this is borderline suspect; most surveys will include a two sigma margin of error, say plus or minus 4 percent here, and the results were within those bounds.

7 0
3 years ago
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