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anzhelika [568]
4 years ago
8

The volume of a sphere is 5,000pi m3. What is the surface area of the sphere to the nearest square meter?

Mathematics
1 answer:
lyudmila [28]4 years ago
7 0
To get the surface area of the sphere, we need to know the radius. Since the volume is given, we can get the radius.
Volume =  \frac{4}{3}π r³
5000πm³ = \frac{4}{3} π r³
5000m³ = \frac{4}{3} r³
5000m³ x 3 = 4r³
\frac{15000m³}{4} = \frac{4r³}{4}<span>
</span>∛3750 = ∛r³

r = 15.536m
r = 15.54m
Since the radius is now known, substitute it directly to the surface area formula
A = 4π x r²
A = 4π x (15.54)²
A= 3,034.67 m² or 3,035 m²
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Find the sum of the geometric series.
sveticcg [70]

Answer:

40/3  option B

Step-by-step explanation:

20-10+5-5/2+ ...

We need to find the sum of infinite geometric series

S_n = \frac{a}{1-r}

a is the first term (20)

r is the common ratio

To find common ratio we divide second term by first term

r=\frac{-10}{20} = -\frac{1}{2}

now we plug in the values

S_n = \frac{20}{1-(-\frac{1}{2}}

S_n = \frac{20}{1+\frac{1}{2}}

S_n = \frac{20}{\frac{3}{2}}

S_n = 20 * \frac{2}{3}

sum = 40/3

7 0
4 years ago
given the following information, determine which lines, if any, are parallel. state the converse that justifies your answer.
frozen [14]

From the information in the diagram found in a similar question online (please see attached drawing), the parallel lines are;

  1. w||z
  2. x||y
  3. x||y
  4. w||z
  5. w||z
  6. x||y
  7. x||y
  8. w||z
  9. x||y
  10. w||z

<h3>What are the relationships between angles formed by parallel lines?</h3>

Parallel lines are lines that do not meet, when extended indefinitely.

The possible information given as obtained from a similar question posted online are;

1. ‹1 is congruent to ‹5

2. ‹7 is congruent to ‹9

3. m‹8 + m‹9 = 180°

4. ‹16 is congruent to ‹14

5. m‹1 + m‹4 = 180°

6. ‹3 is congruent to ‹13

7. ‹2 is congruent to ‹10

8. ‹11 is congruent to ‹15

9. m‹4 + m‹13 = 180°

10. ‹8 is congruent to ‹6

1. Given that ‹1 is congruent to ‹5 where ‹1 and ‹5 are alternate exterior angles, we have that line <em>w </em>is parallel to line <em>z </em>

  • w||z

Theorem (converse); Alternate exterior angles formed by two parallel lines having a common transversal are congruent.

2. ‹7 and ‹9 are alternate interior angles.

Given that ‹7 is congruent to ‹9, therefore;

Line <em>x</em> is parallel to line <em>y</em>

  • x||y

Theorem (converse); Alternate interior angles formed by two parallel lines having a common transversal are congruent.

3. Given that m‹8 + m‹9 = 180°, therefore;

‹8 and ‹9 are supplementary angles, formed between lines <em>x </em>and <em>y</em>.

‹8 and ‹9 are also consecutive interior angles.

Theorem (converse); Consecutive interior angles formed between parallel lines are supplementary.

Therefore;

  • x||y

4. ‹16 and ‹14 are corresponding angles formed by lines <em>w </em>and <em>z</em>.

Theorem (converse); Corresponding angles formed by parallel lines are congruent.

Given ‹16 congruent to ‹14, we have;

  • w||z

5. m‹1 and m‹4 are consecutive exterior angles formed by lines <em>w </em>and <em>z</em>.

Theorem (converse); Consecutive exterior angles formed by two parallel lines are supplementary.

Given that m‹1 + m‹4 = 180°, we have;

  • w||z

6. ‹3 and ‹13 are alternate exterior angles formed by lines <em>x </em>and <em>y</em>.

Theorem (converse); Alternate exterior angles formed by parallel lines are congruent.

Given that ‹3 congruent to ‹13, we have;

  • x||y

7. ‹2 and ‹10 are corresponding angles formed by lines <em>x </em>and <em>y</em>

Given that ‹2 congruent to ‹10, therefore;

  • x||y

8. ‹11 and ‹15 are alternate interior angles formed by lines <em>w </em>and <em>z</em>.

‹11 is congruent to ‹15, therefore;

  • w||z

9. ‹4 and ‹13 are consecutive exterior angles formed by lines <em>x </em>and <em>y</em>

m‹4 + m‹13 = 180°, therefore;

  • x||y

10. ‹8 and ‹6 are corresponding angles formed by lines <em>w </em>and <em>z</em>.

‹8 is congruent to ‹6, therefore;

  • w||z

Learn more about angles formed by parallel lines that have a common transversal here:

brainly.com/question/24607467

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3 0
1 year ago
Please help will give brainliest
notka56 [123]

Answer:

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3 0
3 years ago
The area of the triangle is 22.4cm^2.
Ivanshal [37]

Answer:

The longest side length b is approximately 13.172 cm

Step-by-step explanation:

The given parameters are;

The area of the triangle = 22.4 cm²

The given angles of the triangle = ∠97°

The given side of the triangle = 3.7 cm

The formula for the area of a triangle, A = 1/2 × a × b × sin(C)

Where;

a, and b are the side legs forming the angle C

Therefore,  we have;

A = 22.4 = 1/2 × 3.7 × a × sin(97°)

a =  22.4/(1/2 × 3.7 × sin(97°)) ≈ 12.199

a ≈ 12.199 cm

Therefore, by cosine rule, we have;

b² = a² + c² - 2 × a × c × Cos(B)

Substituting the values, gives;

b² = 12.199² + 3.7² - 2 × 12.199 × 3.7 × Cos(97°)

b² ≈ 173.507

∴ b ≈ √173.507 ≈ 13.172

b ≈ 13.172 cm

6 0
3 years ago
What is half of the fraction 3/4
schepotkina [342]
The half of 3/4 is 0.375, or 3/8. All you have to do is multiply 3/4 times 1/2. 
5 0
3 years ago
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