Which of the statements below are true for linear functions? Select all that apply.

Mathematics

2 answers:

Sati [7]3 years ago

8 0

Answer:

The general equation is y=mx+b

the graph contains a vertex

the slop of the graph is constant and can be defined as rise over run

Bumek [7]3 years ago

6 0

I would go for Y=mx+b

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Find the surface area of the cube. 5 ft S.A. = [?] ft? 5 ft A Hint: A cube has 6 square faces. Find the area of one face, then m

atroni [7]

First, let's find the area of one face of the cube.

Area = base x height

A = 5 x 5 = 25

There are 6 faces on a cube, so we can multiply the area of one face by 6 to get the total surface area.

SA = 25 x 6 = 150 ft^2

Hope this helps!

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3 years ago

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garri49 [273]

Perimeter is adding all the outside dimensions. The left side of the shoae is a rectangle, so the bottom line is the same as the top line, 10 feet.

Perimeter = 8 + 10 + 8.9 + 10 + 4 = 40.9 ft.

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4 years ago

Suppose a parabola has an axis of symmetry at x=-5, a maximum height of 9, and passes through the point (-7,1). Write the equati

Nutka1998 [239]

the parabola has maximum at 9, meaning is a vertical parabola and it opens downwards.

it has a symmetry at x = -5, namely its vertex's x-coordinate is -5.

check the picture below.

so then, we can pretty much tell its vertex is at (-5 , 9), and we also know it passes through (-7, 1)

$\bf ~~~~~~\textit{parabola vertex form} \\\\ \begin{array}{llll} y=a(x- h)^2+ k\qquad \leftarrow \textit{using this one}\\\\ x=a(y- k)^2+ h \end{array} \qquad\qquad vertex~~(\stackrel{}{ h},\stackrel{}{ k}) \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ \begin{cases} h=-5\\ k=9 \end{cases}\implies y=a[x-(-5)]^2+9\implies y=a(x+5)^2+9$

$\bf \textit{we also know that } \begin{cases} x=-7\\ y=1 \end{cases}\implies 1=a(-7+5)^2+9 \\\\\\ -8=a(-2)^2\implies -8=4a\implies \cfrac{-8}{4}=a\implies -2=a \\\\[-0.35em] ~\dotfill\\\\ ~\hfill y=-2(x+5)^2+9~\hfill$