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KIM [24]
4 years ago
12

Solve the equation (1 +2)u, + uy - 0. 5

Mathematics
1 answer:
Kruka [31]4 years ago
7 0

3u(uy-0.5)

Thats the answer

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Given $a \equiv 1 \pmod{7}$, $b \equiv 2 \pmod{7}$, and $c \equiv 6 \pmod{7}$, what is the remainder when $a^{81} b^{91} c^{27}$
Blizzard [7]
\begin{cases}a\equiv1\pmod7\\b\equiv2\pmod7\\c\equiv6\pmod7\end{cases}

a^{81}\equiv1^{81}\equiv1\pmod7

b^{91}\equiv2^{91}\pmod7

2^{91}\equiv(2^3)^{30}\times2^1\equiv8^{30}\times2\pmod7
8\equiv1\pmod7
2\equiv2\pmod7
\implies2^{91}\equiv1^{30}\times2\equiv2\pmod7

c^{27}\equiv6^{27}\pmod7

6^{27}\equiv(-1)^{27}\equiv-1\equiv6\pmod7

\implies a^{81}b^{91}c^{27}\equiv1\times2\times6\equiv12\equiv5\pmod7
6 0
3 years ago
2(x-3)-12 = -4<br> How do I solve this equations
deff fn [24]

Answer:

x= 7

Step-by-step explanation:

1st step: Multiply the factor (outside number) with the numbers and variable(s) in the box. This results in 2(x-3) = 2x-6

2nd Step: continue the rest of the equation since there are no more brackets left so 2x-6-12=-4

3rd Step: send -12 to the other side of the equation (side changes sign changes) so it will become 2x-6=-4+12    (You are actually supposed to make the variable alone on one side of the equation so that you would be able to calculate its value)

4th step: 2x-6=8 ---> send -6 to the other side as well which will then result in 2x=14

5th step: since 2 is being multiplied by x, when you send it to the other side (to make x alone) you will divide 14 by 2 ( sign of 2 changes from multiplication to division)

Final Step: x=7

3 0
3 years ago
Which of the following could be the lengths of the sides of a 30 60 90 triangle?
lord [1]
The answer you’re looking for is 30° perfect
5 0
3 years ago
If sin theta = 2/3 and tan theta &lt;0 what is the value of cos theta?
Mrac [35]

Answer:

d) \cos(\theta)=-\frac{\sqrt{5}}{3}

Step-by-step explanation:

If   \sin(\theta)=\frac{2}{3} and \tan(\theta)\:, then

\theta is in quadrant 2.

Recall that;

\sin^2(\theta)+\cos^2(\theta)=1

We substitute the given sine ratio to obtain;

(\frac{2}{3})^2+\cos^2(\theta)=1

\frac{4}{9}+\cos^2(\theta)=1

\cos^2(\theta)=1-\frac{4}{9}

\cos^2(\theta)=\frac{5}{9}

\cos(\theta)=\pm \sqrt{\frac{5}{9}}

\cos(\theta)=\pm \frac{\sqrt{5}}{3}

We are in the second quadrant, therefore

\cos(\theta)=-\frac{\sqrt{5}}{3}

8 0
4 years ago
Which algebraic expression models the sum of 3 coins and c coins?
SpyIntel [72]
3+c i think that the answer.
7 0
3 years ago
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